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Sholpan [36]
3 years ago
7

The sales is $680 and the commission rate is 6% what is the commission​

Mathematics
1 answer:
MrRa [10]3 years ago
4 0

Answer:

40.80$ would be the commission

Step-by-step explanation:

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Compare the integers -13 and 15
agasfer [191]
-13is negative and is 13 spaces away from 0. 15 is positive and is 15 spaces away from 0.
6 0
3 years ago
In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408

#Define Y:

Y~(11.04,5.7408)

P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291

Hence, the probability of 12 or fewer is 0.8291

b. The  probability that 5 or more fish were caught.

#Using normal approximation:

P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above P(X\geq 5)=0.9968 and a ,P(X\leq 12)=0.7291

P(5\leq X\leq 120\approx P(4.5\leq Y\leq  12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259

Hence, the probability of between 5 and 12 is 0.7259

4 0
3 years ago
If the Math Olympiad Club consists of 11 students, how many different teams of 3 students can be formed for competitions?
vivado [14]

Answer:

165 different teams of 3 students can be formed for competitions

Step-by-step explanation:

Combinations of m elements taken from n in n (m≥n) are called all possible groupings that can be made with the m elements so that:

  • Not all items fit
  • No matter the order
  • Elements are not repeated

That is, a combination is an arrangement of elements where the place or position they occupy within the arrangement does not matter. In a combination it is interesting to form groups and their content.

To calculate the number of combinations, the following expression is applied:

C=\frac{m!}{n!*(m-n)!}

It indicates the combinations of m objects taken from among n objects, where the term "n!" is called "factorial of n" and is the multiplication of all the numbers that go from "n" to 1.

In this case:

  • n: 3
  • m: 11

Replacing:

C=\frac{11!}{3!*(11-3)!}

Solving:

C=\frac{11!}{3!*8!}

being:

  • 3!=3*2*1=6
  • 8!=8*7*6*5*4*3*2*1=40,320
  • 11!=39,916,800

So:

C=\frac{39,916,800}{6*40,320}

C= 165

<u><em>165 different teams of 3 students can be formed for competitions</em></u>

3 0
3 years ago
Always sometimes never: one angle in a triangle is more than 90°
Afina-wow [57]

Answer: sometimes

Step-by-step explanation:

3 0
3 years ago
In the school election James ran against Ben for
PSYCHO15rus [73]
180 votes is the correct answer
8 0
3 years ago
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