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MrRa [10]
3 years ago
12

Choose the correct solution for the given equation x^2-6x=40

Mathematics
2 answers:
Sindrei [870]3 years ago
8 0

Answer:

x=10,-4

Step-by-step explanation:

Move all of the terms to the left and then set x to zero . Then set each factor equal to zero .

shutvik [7]3 years ago
7 0

Answer:

10,-4

Step-by-step explanation:

not sure where the options are but if you were to solve this equation first bring everything to one side.

x^2 - 6x - 40 = 0

factor it

(x-10)(x+4) = 0

set each part to 0

x-10 = 0 and x+4 = 0

solutions are 10 and -4

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I can’t figure this out I need the answer
fredd [130]

Answer:

  • Area 2 = 72 cm²
  • CD = 7 cm

Step-by-step explanation:

For similar figures, side lengths (and any other linear measure) are proportional. Areas are proportional to the square of the scale factor for side lengths.

  Perimeter 1/Perimeter 2 = CD/EF

  21/18 = CD/6

  CD = 6(21/18)

  CD = 7 . . . cm

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  Area 2/Area 1 = (Perimeter 2/Perimeter 1)²

  Area 2/98 = (18/21)²

  Area 2 = 98(6/7)²

  Area 2 = 72 . . . cm²

7 0
2 years ago
The Center for Medicare and Medical Services reported that there were 295,000 appeals for hospitalization and other Part A Medic
Ymorist [56]

Answer:

(a) 0.00605

(b) 0.0403

(c) 0.9536

(d) 0.98809

Step-by-step explanation:

We are given that 40% of first-round appeals were successful (The Wall Street Journal, October 22, 2012) and suppose ten first-round appeals have just been received by a Medicare appeals office.

This situation can be represented through Binomial distribution as;

P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....

where,  n = number of trials (samples) taken = 10

            r = number of success

            p = probability of success which in our question is % of first-round

                   appeals that were successful, i.e.; 40%

So, here X ~ Binom(n=10,p=0.40)

(a) Probability that none of the appeals will be successful = P(X = 0)

     P(X = 0) = \binom{10}{0}0.40^{0}(1-0.40)^{10-0}

                   = 1*0.6^{10} = 0.00605

(b) Probability that exactly one of the appeals will be successful = P(X = 1)

     P(X = 1) = \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                  = 10*0.4^{1} *0.6^{10-1} = 0.0403

(c) Probability that at least two of the appeals will be successful = P(X>=2)

    P(X >= 2) = 1 - P(X = 0) - P(X = 1)

                     = 1 - \binom{10}{0}0.40^{0}(1-0.40)^{10-0} - \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                     = 1 - 0.00605 - 0.0403 = 0.9536

(d) Probability that more than half of the appeals will be successful =             P(X > 0.5)

  For this probability we will convert our distribution into normal such that;

   X ~ N(\mu = n*p=4,\sigma^{2}= n*p*q = 2.4)

  and standard normal z has distribution as;

      Z = \frac{X-\mu}{\sigma} ~ N(0,1)

  P(X > 0.5) = P( \frac{X-\mu}{\sigma} > \frac{0.5-4}{\sqrt{2.4} } ) = P(Z > -2.26) = P(Z < 2.26) = 0.98809

3 0
3 years ago
I need help with this one question.
Tom [10]

Answer:

answer a

Step-by-step explanation:

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3 years ago
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HACTEHA [7]

Answer:

nebraskan Vulunnter na bumaril sa tatlong piliponong sundalo na siyang naging hudyat ng digmaan

Check your spelling or try different keywords

Ref A: D4EA49C383DC4782B921C6733B0FE57B Ref B: SG1EDGE0220 Ref C: 2020-12-08T02:28:46Z

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