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Shalnov [3]
3 years ago
10

Suppose 1,600 of 2,000 registered voters sampled said they planned to vote for the Republican candidate for president. Using the

0.95 degree of confidence, what is the interval estimate for the population proportion (to the nearest 10th of a percent)?
Mathematics
1 answer:
Zinaida [17]3 years ago
5 0

Answer:\left ( 0.781,0.8175\right )

Step-by-step explanation:

Given

Population Proportion \left ( \hat{P}\right )=\frac{1600}{2000}

\hat{P}=0.8

Confidence level =95 %

For 95% confidence interval level is \hat{P} \pm \sqrt{\frac{\hat{P}\left ( 1-\hat{P}\right )}{n}}

=0.8\pm 1.96\sqrt{\frac{\hat{0.8}\left ( 1-\hat{0.8}\right )}{2000}}

=0.8\pm 1.96\times 8.94\times 10^{-3}

The interval lies between \left ( 0.781,0.8175\right )

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Express 245 as a product of its prime factors
antoniya [11.8K]
245= 5*7*7 :) so 5 and 7 are prime factors of 245 :)
7 0
3 years ago
Runner A crosses the starting line of a marathon and runs at an average pace of 5.6 miles per hour. Half an hour later, Runner B
marishachu [46]
Time it took runner A to complete the marathon = 26.2 / 5.6 = 4 hrs 41 mins
Time it took runner B to complete the marathon = 26.2 / 6.4 = 4 hrs 6 mins

Time it took runner B to complete the marathon relative to when runner A started = 30 mins + 4 hrs 6 mins = 4 hrs 36 mins

Therefore, runner B will finnish ahead of runner A.

Let x be the time the two runners are at the same point, then
5.6x + 5.6(0.5) = 6.4x
6.4x - 5.6x = 2.8
0.8x = 2.8
x = 2.8/0.8 = 3.5
Therefore, runner B will catch up with runner A 3.5 hours after runner A starts the race.
<span>Runner B; Runner B will catch up to Runner A 3.5 hours after Runner A crosses the starting line.</span>

5 0
3 years ago
Danielle runs 1/5 of a mile in 4.5 minutes. if she continues at the same speed, how long will it take her to run two miles?
motikmotik
(1/5) / 4.5 = 2 / m....1/5 mile to 4.5 minutes = 2 miles to m minutes
cross multiply
(1/5)(m) = (2)(4.5)
1/5m = 9
m = 9 * 5/1
m = 45 minutes <===
4 0
3 years ago
6y²×3³×18² what do I do
koban [17]

Answer:

52488y²

Step-by-step explanation:

first solve for 3³. then solve for 18²

3³=27

18²=324

27*324=8748

then multiply 8748 by 6y²

=52488y^2

6 0
3 years ago
Surveys conducted in American high schools concluded that 90% of the students in a sample of 400 students had more than one acti
kenny6666 [7]
The sample proportion has an approximately normal distribution, with the mean being the population mean and the standard deviation (i.e. the standard error of the sampling proportion) equal to 

SE = sqrt(p*q/n) where p is the population proportion q is 1-p, and n is the sample size. 

<span>(Typically, for a confkdence interval, the sample proportion and its complement are substituted for p and q.) </span>

The margin of error will be Zc*SE, where Zc is the critical value of Z for the level of confidence required. The confidence interval, then, will be the sample proportion, plus or minus the margin of error. 

For a 90% confidence interval, Zc is 1.645. 

<span>So the margin of error is 1.645 * sqrt(.9*.1/400), roughly .025. So your confidence interval would be around [.875, .925] 


The best and most correct answer among the choices provided by your question is the second choice or letter C which is 3%.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.</span>
4 0
3 years ago
Read 2 more answers
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