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2 years ago

The equation y - 5 = 6X + 1 is written as point-slope form. What is the equation written in slope intercept form

Mathematics

1 answer:

Harrizon [31]2 years ago

3 0

Answer:

y = 6x + 6

Step-by-step explanation:

<h2>The general formula is y = mx +c </h2>

so; the y as seen will be constant as well as the x

With change of subject the 5 will be moved to the other side having y= 6x +1 + 5 .Given us y = 6x + 6.

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Write a problem involving how much more Than and solve it. Explain how drawing a diagram helped you solve the problem

avanturin [10]

A very simple example problem to satisfy the required above is,
"John has 8 apples and 17 oranges. How much more oranges does John has than apple?"

To answer this item, one needs to subtract the number of apples from the number of oranges. This is as shown below,
D = 17 - 8 = 9

The concept of "how much more than" is linked to finding the difference between the numbers.

6 0

3 years ago

Answer number 14. It’s very difficult for me and i need some help.

professor190 [17]

Answer:

1201.2 in (100.1ft)

Step-by-step explanation:

A scale model represents a ratio. All sides must be shrunk or increased based on a constant value. In this case the ratio of the model is 1/13 the size of the original giving us a 1:13 ratio. So each side of your scale model must be multiplied by 13 to find the real value of the side.

First convert all units to inches then divide the width of the real windmill by the width of the scale model (both in inches) you will see the answer is 13. Multiply the inch values of all sides of your model by 13 and this gives you the proportional value of each side of the real windmill in relation to the scale model.

5 0

2 years ago

Mia can run at a rate of 360 feet per minute. Approximately how many minutes would she take to run a 500-yard stretch of road an

tankabanditka [31]

Step-by-step explanation:

since we know, she can run 360 ft per minute, and we want to know how many minutes she would need to run 500 yards we need to find out how often 360 ft fit into 500 yards.

so,

500 yards / 360 ft

how can we make this division ?

help is given to us by taking us that 1 yard = 3 ft.

aha !

so, 500 yards = 500×3 ft = 1500 ft

therefore, our task now looks like

1500 ft / 360 ft

and this we understand and can do, right ?

1500 / 360 = 150/36 = 75/18 = 4 3/18 = 4 1/6 minutes

the closest answer option is therefore 4.2, meaning she would take about 4.2 minutes to run 500 yards.

7 0

2 years ago

a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was

Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

<em>Let </em> $\bar X$ <em> = sample average time spent studying</em>

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = population mean hours spent studying = 25 hours

$\sigma$ = standard deviation = 15 hours

n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < $\bar X$ < 30 hours)

P(29 hours < $\bar X$ < 30 hours) = P( $\bar X$ < 30 hours) - P( $\bar X$ $\leq$ 29 hours)

P( $\bar X$ < 30 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ < $\frac{ 30-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z < 2) = 0.97725

P( $\bar X$ $\leq$ 29 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ $\leq$ $\frac{ 29-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z $\leq$ 1.60) = 0.94520

<em>So, in the z table the P(Z </em> $\leq$ <em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.</em>

Therefore, P(29 hours < $\bar X$ < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0

2 years ago

−4(m+6)=−8 plz answer

dangina [55]

Answer:Divide both sides by the numeric factor on the left side, then solve.

−

Step-by-step explanation:

5 0

3 years ago