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Andrei [34K]
3 years ago
10

If the members of the team are selected at random, what is the probability that 2 men and 2 women will be selected?

Mathematics
1 answer:
Norma-Jean [14]3 years ago
4 0
N1=4,P 1=0.5.50 THINK
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A square parking lot has an area of 12,996 square yards. a. What is the length of one side of the parking lot? b. How many yards
jenyasd209 [6]

Answer:

114 yards

456 yards

Step-by-step explanation:

Given that:

Area of square parking lot = 12,996 square yards

The lenght of one side of the parking lot :

Area of a square = a² ; a = side length

Hence ;

12996 = a²

√12996 = a

114 = a

Hence, length of one side = 114 yards

Yards of fence needed to enclose parking lot :

Perimeter of a square = 4a ; a = side length

Perimeter = 4(114)

Perimeter = 456 yards

7 0
3 years ago
PLZ help thanks!!!! A shipment of 10 tons of sugar is separated into containers of equal size. If the shipment fills 3 3/4 conta
slava [35]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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Use the figure to find the product (x + 3)(x + 2). (Hint: Find the area of each small square or rectangle, then add.)
Keith_Richards [23]
(x+3)(x+2)
x^2+2x+3x+6
x^2+5x+6<<<<<< answer
5 0
3 years ago
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How many groups of 1/2 days are in 1 week? Write a multiplication equation or a division equation to represent the question, the
worty [1.4K]

Answer:

14 groups

Step-by-step explanation:

Given

Groupings = \frac{1}{2}\ day

Duration = 1\ week

Required

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To do this, we simply divide the duration by the number half day group.

This gives:

Group = \frac{Duration}{Groupings}

Group = \frac{1\ week}{1/2\ days}

Convert week to days

Group = \frac{7\ days}{1/2\ days}

Group = \frac{7}{1/2}

Group = 7 / \frac{1}{2}

Convert to multiplication

Group = 7 * \frac{2}{1}

Group = \frac{14}{1}

Group = 14

<em>Hence, there are 14 groups</em>

4 0
3 years ago
Which expressions are equivalent to the given expression?
gizmo_the_mogwai [7]

Answer: Choice C. \frac{1}{x^{2}y^{5}  }and Choice E. x^{-2} y^{-5}

Step-by-step explanation:

Algebraic exponents.

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