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nadya68 [22]
2 years ago
11

A square parking lot has an area of 12,996 square yards. a. What is the length of one side of the parking lot? b. How many yards

of fence will it take to enclose the entire parking lot?
Mathematics
1 answer:
jenyasd209 [6]2 years ago
7 0

Answer:

114 yards

456 yards

Step-by-step explanation:

Given that:

Area of square parking lot = 12,996 square yards

The lenght of one side of the parking lot :

Area of a square = a² ; a = side length

Hence ;

12996 = a²

√12996 = a

114 = a

Hence, length of one side = 114 yards

Yards of fence needed to enclose parking lot :

Perimeter of a square = 4a ; a = side length

Perimeter = 4(114)

Perimeter = 456 yards

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-12=4(x-7)-8x

One solution was found :

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Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :


                    -12-(4*(x-7)-8*x)=0


Step by step solution :

Step  1  :

Equation at the end of step  1  :

 -12 -  (4 • (x - 7) -  8x)  = 0

Step  2  :

Step  3  :

Pulling out like terms :

3.1     Pull out like factors :


  4x + 16  =   4 • (x + 4)


Equation at the end of step  3  :

 4 • (x + 4)  = 0

Step  4  :

Equations which are never true :

4.1      Solve :    4   =  0

Hope this helps you, Have a nice day.

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Read 2 more answers
Bill is able to save $35/week after working part-time and paying his expenses. These two formulas show his weekly savings: f(1)
Umnica [9.8K]
1. We use the recursive formula to make the table of values:
f(1) = 35
f(2) = f(1) + f(2-1) = f(1) + f(1) = 35 + 35 = 70
f(3) = f(1) + f(3-1) = f(1) + f(2) = 35 + 70 = 105
f(4) = f(1) + f(4-1) = f(1) + f(3) = 35 + 105 = 140
f(5) = f(1) + f(5-1) = f(1) + f(4) = 35 + 140 = 175

2. We observe that the pattern is that for each increase of n by 1, the value of f(n) increases by 35. The explicit equation would be that f(n) = 35n. This fits with the description that Bill saves up $35 each week, thus meaning that he adds $35 to the previous week's value.

3. Therefore, the value of f(40) = 35*40 = 1400. This is easier than having to calculate each value from f(1) up to f(39) individually. The answer of 1400 means that Bill will have saved up $1400 after 40 weeks.

4. For the sequence of 5, 6, 8, 11, 15, 20, 26, 33, 41...
The first-order differences between each pair of terms is: 1, 2, 3, 4, 5, 6, 7, 8...since these differences form a linear equation, this sequence can be expressed as a quadratic equation. Since quadratics are functions (they do not have repeating values of the x-coordinate), therefore, this sequence can also be considered a function.
4 0
3 years ago
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