Question

What is the direction (angle) of the resultant vector?

Answer 1

Answer:

$\theta = 148.8$

Step-by-step explanation:

Given

$R_x = -419$

$R_y = -253$

$R = 490$

Required

Determine the value of $\theta$

Since, $\theta$ is counter clockwise from x axis;

The relationship between $\theta$, $R_x$ and R is

$cos\theta = \frac{R_x}{R}$

Substitute values for Rx and R

$cos\theta = \frac{-419}{490}$

$cos\theta = -0.8551$

Take arccos of both sides

$\theta = cos^{-1}(-0.8551)$

$\theta = 148.770784108$

$\theta = 148.8$ (Approximated)