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Aleonysh [2.5K]
3 years ago
10

Which is the graph of f(x) = 2(3)x?

Mathematics
2 answers:
Andreyy893 years ago
6 0

Answer:

The last graph.

Hope this helps.

aliya0001 [1]3 years ago
4 0

I'm assuming the equation should be f(x) = 2(3)^x

If so, then plug in x = 1 to find that

f(x) = 2(3)^x\\\\f(1) = 2(3)^1\\\\f(1) = 2(3)\\\\f(1) = 6\\\\

Showing the point (x,y) = (1,6) is on the curve. Only choice A reflects this. So choice A is the answer.

Choices B,C, and D can be ruled out. For instance, with choice B, plugging in x = 2 leads us to get

f(x) = 2(3)^x\\\\f(2) = 2(3)^2\\\\f(2) = 2(9)\\\\f(2) = 18\\\\

Indicating that (2,18) is on the curve instead of (2,12). This shows choice B is not a a valid answer. Similar situations will happen with C and D.

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Find the value of x and y
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Answer:

  • x = 12
  • y = 20

Step-by-step explanation:

There is nothing in this diagram to suggest any particular values for x and y.

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If we assume the figure is intended to be a kite, symmetrical about its horizontal diagonal, then each segment is congruent to the one above it.

  x = 12

  y = 20

4 0
3 years ago
Add (3d+2)+(4d+9) ixl
Elodia [21]

Answer:

7d+11

Step-by-step explanation:

Pretty much just addition.

3d+4d+2+9

(3d+2)+(4d+9) = 7d+11.

7 0
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4 years ago
You are downsizing. Your new residence will have much less closet space than does your current home. You have 12 pair of long pa
harkovskaia [24]

Answer:

a) there are 7,854,000 number of ways the random selections can be arranged

b) the required probability is 0.0445

Step-by-step explanation:

Given that;

you have 12 pair of long pants, 6 pair of short pant and 17 t-shirt which in total;

Total = 12 + 6 + 17 = 35

a) number of ways a random selection of 9 pair of long pants, 4 pair of short pants and 13 t-shirts can be arranged;

⇒ [ 12   ×    [ 6     ×    [ 17

     9 ]          4 ]           13 ]

= (12! / (9! 3!)) (6! / (4! 2!)) (17! / (13! 4!))

= (220) (15) (2380)

= 7,854,000

Therefore there are 7,854,000 number of ways the random selections can be arranged

b)

Number of ways of selecting 25 item from 35 items;

⇒ [ 35        

    25 ]

=

(35! / (25! 10!) = 183.579,396

now number of ways to select 10 pair of long pants, 3 pairs of short pantts and 12 t-shirt;

⇒ [ 12   ×    [ 6     ×    [ 17

     10 ]         3 ]           12 ]

= (12! / (10! 2!)) (6! / (3! 3!)) (17! / (12! 5!))

= (66) (20) (6188)

= 8,168,160

So, Required probability = 8,168,160 / 183,579,396

= 0.0445

So the required probability is 0.0445

5 0
3 years ago
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