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galina1969 [7]
2 years ago
8

if you multiply both sides of an equation by the same number the new equation will have the same solution

Mathematics
1 answer:
asambeis [7]2 years ago
4 0

Answer:

Yes, the new equation that we get after multiplying the same number to both sides of an equation, will have the same solution.

Step-by-step explanation:

Yes, the new equation that we get after multiplying the same number to both sides of an equation, will have the same solution.

This is because we know from the property of an equation that common numbers of two sides of an equation cancel each other and the equation gets simplified.

So, if we multiply the same number to both sides of an equation then the common multiplier gets automatically canceled out and finally, the original equation remains the same.  

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PLEASE HELP .!!! ILL GIVE BRAINLIEST.. *EXRTA POINTS* .. DONT SKIP :(( ! <br> ILL GIVE 40 POINTS .
Naya [18.7K]
I would say the answer is 7, since 21 divided by 3 is 7 and there are 1/3 as many of them
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3 years ago
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For the function y = 15x – 4, assume the domain is only values of x from 0 to 5. What is the range of the function?​
Harrizon [31]
X = 0 y = 15(0) - 4 = -4
x = 1 y = 15(1) - 4 = 11
x = 2 y = 15(2) - 4 = 26
x = 3 y = 15(3) - 4 = 41
x = 4 y = 15(4) - 4 = 56
x = 5 y = 15(5) - 4 = 71
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After the party, 3 1⁄4 pecan pies remained. The next day, Edward's family ate 1 1⁄4 of a pie. How many pecan pies were left?
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2 pecan pies were left.
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2 years ago
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Compute the exact value of the function for the given x-value without using a calculator. f(x) = 7x for x = 2
Bas_tet [7]

Answer:

14

Step-by-step explanation:

Substitute x = 2 into f(x)

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6 0
3 years ago
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HighTech Inc. randomly tests its employees about company policies. Last year in the 560 random tests conducted, 26 employees fai
Tanzania [10]

Answer:

The 98% confidence interval for the proportion of applicants that fail the test is (0.025, 0.067).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

560 random tests conducted, 26 employees failed the test. This means that n = 560, \pi = \frac{26}{560} = 0.046

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.33.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.046 - 2.33\sqrt{\frac{0.046*0.954}{560}} = 0.025

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.046 + 2.33\sqrt{\frac{0.046*0.954}{560}} = 0.067

The 98% confidence interval for the proportion of applicants that fail the test is (0.025, 0.067).

5 0
3 years ago
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