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natima [27]
2 years ago
11

Need this answered please!!

Mathematics
1 answer:
Paraphin [41]2 years ago
6 0
<h2>ABC and DEF</h2>

Their 3 angles are equal (64,26,90)

Hope this will help...

Please mark as brainliest

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Please help me... What is the value of X?<br> .
rusak2 [61]
X = 46
because "the c shape" has angles that add up to 180
180-134 = 46
5 0
2 years ago
HELP ASAP!! What is the average rate of change between x = -3 and x = 4 for the equation y = 8x2?
Llana [10]

Answer:

x=-3\\y=8(-3)^2\\y=8(9)\\y=72

x=4\\y=8(4)^2\\y=8(16)\\y=128

128-72=56

average rate of change is 56

Step-by-step explanation:

Plz let me know if im right

3 0
2 years ago
Given: KLMN is a trapezoid m∠N = m∠KML ME ⊥ KN , ME = 3 5 , KE = 8, LM KN = 3 5 Find: KM, LM, KN, Area of KLMN
prisoha [69]
A) Find KM∠KEM is a right angle hence ΔKEM is a right angled triangle Using Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides we can answer the 
KM² = KE² + ME²KM² = 8² + (3√5)²       = 64 + 9x5KM = √109KM = 10.44
b)Find LMThe ratio of LM:KN is 3:5 hence if we take the length of one unit as xlength of LM is 3xand the length of KN is 5x ∠K and ∠N are equal making it a isosceles trapezoid. A line from L that cuts KN perpendicularly at D makes KE = DN
KN = LM + 2x 2x = KE + DN2x = 8+8x = 8LM = 3x = 3*8 = 24
c)Find KN Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have the same height ME = LD.
∠K = ∠N  Hence KE = DN the distance ED = LMhence KN = KE + ED + DN since ED = LM = 24and KE + DN = 16KN = 16 + 24 = 40
d)Find area KLMNArea of trapezium can be calculated using the  formula below Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)substituting values into the general equationArea = 1/2 * ME * (KN+ LM)          = 1/2 * 3√5 * (40 + 24)         = 1/2 * 3√5 * 64         = 3 x 2.23 * 32         = 214.66 units²
7 0
3 years ago
A group of farmers planted 62 fields of vegetables. of the fields they planted, 4/5 were planted with cabbage. how many fields o
chubhunter [2.5K]
Total number of fields of vegetables = 62

Thus,

The amount of fields that is cabbage = \frac{4}{5} * 62 =  \frac{248 }{5} = 49.8


4 0
3 years ago
The midpoint between 94.68 and 49.67
Brilliant_brown [7]

Answer:

72.175

Step-by-step explanation:

The first step is subtract 94.68 by 49.67 which would be 45.01

The next step would be to use 45.01 and divide by two

The last step would be subtract 94.68 by 22.505 and you would get 72.175

Therefore your answer would be 72.175

8 0
3 years ago
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