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MAVERICK [17]
3 years ago
10

In a linked chain implementation of a stack ADT the performance of popping am emtry from the stack is

Computers and Technology
1 answer:
Mice21 [21]3 years ago
8 0

Answer:

B.O(1)

Explanation:

When we are implementing ADT stack using linked chain we can pop an entry from the stack having O(1) time complexity because in linked chain we have the head or top pointer in linked chain only.Popping and pushing in stack happens on only one end that is top.So we have move to move top in linked chain to the next and delete prev node.

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Every windows service has the 3 start types what are those service types?
spayn [35]

Answer:

You can stop, pause, start, delay start, or resume each service as appropriate. You can also modify the start mechanism (Manual or Automatic) or specify an account. Windows Services broadly fall into three categories depending on the actions and applications they control: Local Services, Network Services and System.

5 0
2 years ago
If we are using an 4-character password that contains only lowercase English alphabetic characters (26 different characters), ho
Trava [24]

Answer:

11,424,400 possible passwords

Explanation:

Since all characters are letters and only lowercase

we have 26∧4 = 456,976 possibilities

For a 5-character password which is still lower case sensitive.

we have 26∧5 = 11,881,376 possibilities

Many more possible passwords = (11881376-456976)

= 11,424,400 possible passwords

6 0
3 years ago
Read 2 more answers
What model involves the creation of data and process models during the development of an application
matrenka [14]

Answer:

Data modeling

Explanation:

Data modeling is a term used in computer or software engineering. It is a technique of creating a data model for an information system through unusual formal methods. It also involves the analysis of models during the development of an application. It is further divided into three places including:

1. Conceptual data

2. Logical data model

3. Physics data model

Hence, Data modeling is a model that involves the creation of data and process models during the development of an application

6 0
3 years ago
Which program will have the output shown below?
kumpel [21]

for count in range(5, 8):

   print(count)

This will produce.

5

6

7

I hope this helps!

5 0
3 years ago
Develop a C program that calculates the final score and the average score for a student from his/her (1)class participation, (2)
Ghella [55]

Answer:

#include <iomanip>

#include<iostream>

using namespace std;

int main(){

char name[100];

float classp, test, assgn, exam, prctscore,ave;

cout<<"Student Name: ";

cin.getline(name,100);

cout<<"Class Participation: "; cin>>classp;

while(classp <0 || classp > 100){  cout<<"Class Participation: "; cin>>classp; }

cout<<"Test: "; cin>>test;

while(test <0 || test > 100){  cout<<"Test: "; cin>>test; }

cout<<"Assignment: "; cin>>assgn;

while(assgn <0 || assgn > 100){  cout<<"Assignment: "; cin>>assgn; }

cout<<"Examination: "; cin>>exam;

while(exam <0 || exam > 100){  cout<<"Examination: "; cin>>exam; }

cout<<"Practice Score: "; cin>>prctscore;

while(prctscore <0 || prctscore > 100){  cout<<"Practice Score: "; cin>>prctscore; }

ave = (int)(classp + test + assgn + exam + prctscore)/5;

cout <<setprecision(1)<<fixed<<"The average score is "<<ave;  

return 0;}

Explanation:

The required parameters such as cin, cout, etc. implies that the program is to be written in C++ (not C).

So, I answered the program using C++.

Line by line explanation is as follows;

This declares name as character of maximum size of 100 characters

char name[100];

This declares the grading items as float

float classp, test, assgn, exam, prctscore,ave;

This prompts the user for student name

cout<<"Student Name: ";

This gets the student name using getline

cin.getline(name,100);

This prompts the user for class participation. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Class Participation: "; cin>>classp; </em>

<em> while(classp <0 || classp > 100){  cout<<"Class Participation: "; cin>>classp; } </em>

This prompts the user for test. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Test: "; cin>>test; </em>

<em> while(test <0 || test > 100){  cout<<"Test: "; cin>>test; } </em>

This prompts the user for assignment. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Assignment: "; cin>>assgn; </em>

<em> while(assgn <0 || assgn > 100){  cout<<"Assignment: "; cin>>assgn; } </em>

This prompts the user for examination. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Examination: "; cin>>exam; </em>

<em> while(exam <0 || exam > 100){  cout<<"Examination: "; cin>>exam; } </em>

This prompts the user for practice score. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Practice Score: "; cin>>prctscore; </em>

<em> while(prctscore <0 || prctscore > 100){  cout<<"Practice Score: "; cin>>prctscore; } </em>

This calculates the average of the grading items

ave = (int)(classp + test + assgn + exam + prctscore)/5;

This prints the calculated average

cout <<setprecision(1)<<fixed<<"The average score is "<<ave;  

8 0
3 years ago
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