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3 years ago

50 POINTS & BRAINLIEST!!!! HELP ASAP!!!

Mathematics

1 answer:

Allisa [31]3 years ago

3 0

6(2x - 11) + 15 = 21

First step use distributive property on the left side to remove the parenthesis, to do this multiply 6 by each term inside the parenthesis:

12x - 66 + 15 = 21

Second step, simplify the left side by combining the like terms:

12x - 51 = 21

Third step, add 51 to both sides of the equation:

12x = 72

Last step, divide both sides by 12:

x = 72/12

x = 6

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Help please im lost and not good in math

Damm [24]

Answers: a = 49
b = 10
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3 years ago

Read 2 more answers

An air conditioning technician charged Robert $77.25 to repair his air conditioning system after 3 hours of work. The technician

agasfer [191]

Answer:B

Step-by-step explanation:

He charged the man $25.75 for each hour and he worked for 3 hours so multiply $25.75 x 3 = $77.25

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2 years ago

Solve <img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D

Nostrana [21]

Answer:

$\displaystyle \begin{cases} \displaystyle {x} _{1} = - p \\ \displaystyle x _{2} = - q \end{cases}$

Step-by-step explanation:

we would like to solve the following equation for x:

$\displaystyle \frac{1}{p} + \frac{1}{q} + \frac{1}{x} = \frac{1}{p + q + x}$

to do so isolate $\frac{1}{x}$ to right hand side and change its sign which yields:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{1}{p + q + x} - \frac{1}{x}$

simplify Substraction:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{x - (q + p + x)}{x(p + q + x)}$

get rid of only x:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{ - (q + p )}{x(p + q + x)}$

simplify addition of the left hand side:

$\displaystyle \frac{q + p}{pq} = \frac{ - (q + p )}{x(p + q + x)}$

divide both sides by q+p Which yields:

$\displaystyle \frac{1}{pq} = \frac{ -1}{x(p + q + x)}$

cross multiplication:

$\displaystyle x(p + q + x) = - pq$

distribute:

$\displaystyle xp + xq + {x}^{2} = - pq$

isolate -pq to the left hand side and change its sign:

$\displaystyle xp + xq + {x}^{2} + pq = 0$

rearrange it to standard form:

$\displaystyle {x}^{2} + xp + xq + pq = 0$

now notice we end up with a quadratic equation therefore to solve so we can consider factoring method to use so

factor out x:

$\displaystyle x( {x}^{} + p ) + xq + pq = 0$

factor out q:

$\displaystyle x( {x}^{} + p ) +q (x + p)= 0$

group:

$\displaystyle ( {x}^{} + p ) (x + q)= 0$

by Zero product property we obtain:

$\displaystyle \begin{cases} \displaystyle {x}^{} + p = 0 \\ \displaystyle x + q= 0 \end{cases}$

cancel out p from the first equation and q from the second equation which yields:

$\displaystyle \begin{cases} \displaystyle {x}^{} = - p \\ \displaystyle x = - q \end{cases}$

and we are done!

3 0

3 years ago

I am in need of help

kvv77 [185]

CAD= BAD
AD=AD( the same side of two angles).

8 0

2 years ago

Can someone plz help me? :(

TiliK225 [7]

the answer to your question is B.) 12x

7 0

2 years ago