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Liono4ka [1.6K]
2 years ago
6

Janine plans to deposit $20,000 at the end of each year for eight years into an investment account. The mutual funds containing

stocks what continue to yield 6% per year. Find the future value.
Mathematics
1 answer:
Leto [7]2 years ago
3 0

Answer:

$197,949.40

Step-by-step explanation:

Just took the quiz.

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I WILL GIVE BRAINLIST, DUE IN 15 MIN
Burka [1]

Answer:

$34.50

Step-by-step explanation:

At 3.45 for 3/4 pounds that = to 4.60 for 1 pound.

4.60 *7.5 pounds= $34.50

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2 years ago
I have a 65 in math is that a B or a C
Svetradugi [14.3K]
Its actually a D-.. . .
7 0
3 years ago
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An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
2 years ago
What is the value of 4³ pls help for quiz 10 points
loris [4]

Answer:

64

Step-by-step explanation:

8 0
2 years ago
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Write the equation of the line passing through the points (2,-5) and (7,-3).
Grace [21]

Answer:

5y·2x=21

<em>\frac{y - y1}{y2 - y1}  =  \frac{x - x1}{x2 - x1}</em>

Step-by-step explanation:

using the formula above,you will find the equation 5y–2x=21

7 0
2 years ago
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