3 years ago

AB passes through a A(-3,0) B(-6,5) what is the equation of the line that passes through the origin and is parallel to AB

1 answer:

6 0

Slope = (5 - 0)/(-6 + 3) = -5/3

passes through the origin
y = mx + b
0 = -5/3(-3) + b
b = -5

equation

y = -5/3x - 5

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Order of Operations: BPEMDAS
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Step-by-step explanation:

Step 1: Define expression

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