Answer: It dosn't show anything for me. did you post it?
Assuming the five frame is for the number five (5) then place 5 counters in the frame.
Given: y = 2x^2 - 32x + 56
1) y = 2 [ x^2 - 16x] + 56
2) y = 2 [ (x - 8)^2 - 64 ] + 56
3) y = 2 (x - 8)^2 - 128 + 56
4) y = 2 (x - 8)^2 - 72 <----------- answer
Minimum = vertex = (h,k) = (8, - 72)
=> x-ccordinate of the minimum = 8 <-------- answer
3 is in the tens and 1 is in the ones. To explain more easily... 30+1 is 31.<span />
18- j
19- c
20- h
Hope this is right lol
