I draw the two triangles, see the picture attached.
As you can see, angle 1 and 2 are vertically opposite angles because they are formed by the same two crossing lines and they face each other.
Angles <span>ABQ and QPR, as well as angles BAQ and QRP, are alternate interior angles because they are formed by </span><span>two parallel lines crossed by a transversal, and they are inside the two lines on opposite sides of the transversal.</span>
Hence, Allison's correct claims are:
1 = 2 because they are vertically opposite angles. BAQ = QRP because they are alternate interior angles. Therefore Allison, in order to prove her claim, can use the AA similarity theorem: if two angles of a triangle are congruent to two angles of the other triangle, then the two triangles are similar.
We need to use the Point slope formula to find the slope so we label
(2 , -8);(-1 , 16) subtract
x1 y1 x2 y2. y2-y1/x2-x1
16-(-8)/-1-2 = 24/-3 = -8
meaning the slope of this line is (-8)
Answer:
hmmmmm
Step-by-step explanation: