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4 years ago

What to multiply 2/3 by

Mathematics

1 answer:

LenKa [72]4 years ago

3 0

You will do 60/2 to = 30 because the ratio of peaches to cherries is 2:3 and they need to have a unknown number of peaches lets say thats “x” therefore 60/2=x ,x=30 cups of peaches

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Which logarithmic equation is equivalent to 82 = 64?

34kurt

Answer: Choice B

$2 = \log_{8}(64)$

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Explanation:

The original equation is $8^2 = 64$ with 8 as the base. That is also the base of the log when we get the final answer shown above. Logs are useful to isolate the exponent.

The general rule is that $\text{y} = b^{\text{x}}$ is equivalent to the log form of $\text{x} = \log_{b}(\text{y})$ where b is the base of each.

8 0

2 years ago

Read 2 more answers

HELP. I NEED UR HELP. THIS IS DUE AT 2:30 IM SERIOUS PLEASE HELP ME. DONT IGNORE THIS PLEASE, ITS ONLY 2 QUESTIONS, HELP A POOR

mafiozo [28]

Cannot see all of the first question but for the paint question: if he’s got 1 1/3 gallons and 3/6 gallons already, 3/6 can be reduced to 1/2 then added to the 1 1/3 to give him a total of 1 3/4 gallons. 4 1/2 - 1 3/4 means he’ll need 2 and 3/4 gallons.

6 0

3 years ago

Pls help being timed

Sloan [31]

He needs 9 hours

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3 0

3 years ago

Help

Flauer [41]

A) Measure of Angle L is 67.5. Angle F & Angle L are alternate interior angles.

b) Measure of Angle E is 112.5, because we know that F and H are vertical angles, so therefore they’re congruent. We also know H and E are adjacent, so H + E = 180.

c) Angles E and K are alternate exterior angles. Measure of Angle K is 112.5.

d) Measure of Angle H is 67.5, because we know that Angle F, which is vertical to Angle H, is 67.5. Vertical angles are congruent.

e) Measure of Angle I is 112.5, because Angle I and Angle K are vertical angles.

f) They’re corresponding angles.

3 0

2 years ago

ANSWER ASAP PLZ!!

Vikentia [17]

$\text{If is}\\\\\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2\end{array}$

Answer:

$\large\boxed{\left(-\dfrac{344}{69},\ -\dfrac{38}{3}\right)}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2&\text{multiply both sides by (-0.3)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}0.2-0.3y=4\\-0.69x+0.3y=-0.36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-0.69x+0.2=3.64\qquad\text{subtract 0.2 from both sides}\\.\qquad-0.69x=3.44\qquad\text{divide both sides by (-0.69)}\\.\qquad x=-\dfrac{3.44\cdot100}{0.69\cdot100}\\.\qquad \boxed{x=-\dfrac{344}{69}}\\\\\text{Calculate the value of y from first equation:}$

$0.2-0.3y=4\qquad\text{subtract 0.2 from both sides}\\-0.3y=3.8\qquad\text{divide both sides by (-0.3)}\\y=-\dfrac{3.8\cdot10}{0.3\cdot10}\\\boxed{y=-\dfrac{38}{3}}$

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$\text{If is}\\\\\left\{\begin{array}{ccc}0,2x-0,3y=4\\2.3x-y=1.2\end{array}\right$

Answer:

$\large\boxed{\left(-\dfrac{52}{7},\ -\dfrac{128}{7}\right)}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}0.2x-0.3y=4&\text{multiply both sides by 10}\\2.3x-y=1.2&\text{multiply both sides by 10}\end{array}\right\\\\\left\{\begin{array}{ccc}2x-3y=40&\text{multiply both sides by (-10)}\\23x-10y=12&\text{multiply both sides by 3}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-20x+30y=-400\\69x-30y=36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad49x=-364\qquad\text{divide both sides by 49}\\x=-\dfrac{364:7}{49:7}\\.\qquad\boxed{x=-\dfrac{52}{7}}$

$2\left(-\dfrac{52}{7}\right)-3y=40\\-\dfrac{104}{7}-3y=40\qquad\text{multiply both sides by 7}\\-104-21y=280\qquad\text{add 104 to both sides}\\-21y=384\qquad\text{divide both sides by (-21)}\\y=-\dfrac{384:3}{21:3}\\\boxed{y=-\dfrac{128}{7}}$

7 0

4 years ago