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Rama09 [41]
3 years ago
11

How do you know when all of the bromine has been consumed? Group of answer choices1. It will all be consumed by the cinnamic aci

d since you're using equal moles of each 2. It will be consumed as soon as you add some cyclohexene3. It will be consumed as soon as you add some sodium bisulfite 4. When the solution turns clear, either at the end of the reaction or when you add sufficient cyclohexene
Chemistry
1 answer:
Rzqust [24]3 years ago
6 0

Answer:

When the solution turns clear, either at the end of the reaction or when you add sufficient cyclohexene

Explanation:

The colour of bromine in the solution is usually yellow, however when the solution turns clear, this shows that all the bromine has been consumed.

Another way to make sure that all the bromine molecules are consumed is by addition of an unsaturated hydrocarbon like cyclohexene. Cyclohexene will consume the bromine molecules and the solution will become clear, while the cyclohexene becomes more saturated by becoming bromo cyclohexane.

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What are the properties of liquids
bixtya [17]

the properties of liquids usally wet, wet shows expiation on heating and contracting on cooling

3 0
3 years ago
Derive an expression for the molar mass of a gas starting with its density?
notka56 [123]

Answer:

The relationships between molar mass and density for a monoatomic gas can be easy.  

The Ideal Gas Law, PV = nRT can be arranged so that n moles equals the mass/molar mass of the gas to become,

PV =  

M

mRT

​  

 

where m is the mass and M is the molar mass.

M =  

PV

mRT

​  

, if you hold the temperature of the gas constant the equation reduces to the Boyle's law or  

PV

m

​  

 

The mass will be constant assuming the container is closed and so the gas cannot be escaped so, PV will be constant.  

D =  

V

m

​  

 and M =  

PV

mRT

​  

 

M =  

P

DRT

​  

 

The higher the density of the gas the higher the molar mass and vice versa.

Explanation:

6 0
3 years ago
Concerning the 10.0 mL of 0.50 M NaCl to 100 mL of solution: When a solution is diluted, does it change the number of moles diss
Mars2501 [29]

No, the dilution does not change the number of moles dissolved

Explanation:

We can see that,

The molarity of the solution was 0.50 M

The volume of the solution is 10 ml.

No of moles of the solute was= volume * concentration

                                                   = 10 X 10^-3* 0.50

                                                     = 5*10^-3 moles

When the solution is diluted from 10 ml to 100ml, the molarity or concentration  changes but number of moles remains constant.

The molarity of 100 ml solution will be

c=n/V

  = 5*10^-3*/100*10^-3

  = 0.05

  when the solution is diluted to 100ml from 10 ml molarity changes from 0.5M TO 0.05 M

8 0
3 years ago
Read 2 more answers
Set up a ripple tank with a wave generator on one side.
Simora [160]

when the waves pass from the deeper water to the shallower water its speed will decrease.

<h3>What is refraction of wave?</h3>

Refraction of wave is the change in direction of a wave passing from one medium to another caused by its change in speed.

For example, waves travel faster in deep water than in shallower water.

Thus, we can conclude that when the waves pass from the deeper water to the shallower water its speed will decrease.

Learn more about refraction of waves here: brainly.com/question/1360744

#SPJ1

6 0
2 years ago
The temperature of a 95.4 g piece of Cu increases from 25.0 °C to 48.0 °C when the Cu absorbs 849 J of heat. What is the specifc
melisa1 [442]
<h3>Answer:</h3>

0.387 J/g°C

<h3>Explanation:</h3>
  • To calculate the amount of heat absorbed or released by a substance we need to know its mass, change in temperature and its specific heat capacity.
  • Then to get quantity of heat absorbed or lost we multiply mass by specific heat capacity and change in temperature.
  • That is, Q = mcΔT

in our question we are given;

Mass of copper, m as 95.4 g

Initial temperature = 25 °C

Final temperature = 48 °C

Thus, change in temperature, ΔT = 23°C

Quantity of heat absorbed, Q as 849 J

We are required to calculate the specific heat capacity of copper

Rearranging the formula we get

c = Q ÷ mΔT

Therefore,

Specific heat capacity, c = 849 J ÷ (95.4 g × 23°C)

                                        = 0.3869 J/g°C

                                        = 0.387 J/g°C

Therefore, the specific heat capacity of copper is 0.387 J/g°C

3 0
3 years ago
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