the properties of liquids usally wet, wet shows expiation on heating and contracting on cooling
Answer:
The relationships between molar mass and density for a monoatomic gas can be easy.
The Ideal Gas Law, PV = nRT can be arranged so that n moles equals the mass/molar mass of the gas to become,
PV =
M
mRT
where m is the mass and M is the molar mass.
M =
PV
mRT
, if you hold the temperature of the gas constant the equation reduces to the Boyle's law or
PV
m
The mass will be constant assuming the container is closed and so the gas cannot be escaped so, PV will be constant.
D =
V
m
and M =
PV
mRT
M =
P
DRT
The higher the density of the gas the higher the molar mass and vice versa.
Explanation:
No, the dilution does not change the number of moles dissolved
Explanation:
We can see that,
The molarity of the solution was 0.50 M
The volume of the solution is 10 ml.
No of moles of the solute was= volume * concentration
= 10 X 10^-3* 0.50
= 5*10^-3 moles
When the solution is diluted from 10 ml to 100ml, the molarity or concentration changes but number of moles remains constant.
The molarity of 100 ml solution will be
c=n/V
= 5*10^-3*/100*10^-3
= 0.05
when the solution is diluted to 100ml from 10 ml molarity changes from 0.5M TO 0.05 M
when the waves pass from the deeper water to the shallower water its speed will decrease.
<h3>
What is refraction of wave?</h3>
Refraction of wave is the change in direction of a wave passing from one medium to another caused by its change in speed.
For example, waves travel faster in deep water than in shallower water.
Thus, we can conclude that when the waves pass from the deeper water to the shallower water its speed will decrease.
Learn more about refraction of waves here: brainly.com/question/1360744
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<h3>
Answer:</h3>
0.387 J/g°C
<h3>
Explanation:</h3>
- To calculate the amount of heat absorbed or released by a substance we need to know its mass, change in temperature and its specific heat capacity.
- Then to get quantity of heat absorbed or lost we multiply mass by specific heat capacity and change in temperature.
- That is, Q = mcΔT
in our question we are given;
Mass of copper, m as 95.4 g
Initial temperature = 25 °C
Final temperature = 48 °C
Thus, change in temperature, ΔT = 23°C
Quantity of heat absorbed, Q as 849 J
We are required to calculate the specific heat capacity of copper
Rearranging the formula we get
c = Q ÷ mΔT
Therefore,
Specific heat capacity, c = 849 J ÷ (95.4 g × 23°C)
= 0.3869 J/g°C
= 0.387 J/g°C
Therefore, the specific heat capacity of copper is 0.387 J/g°C