2C₂H₂ + 5O₂ = 4CO₂ + 2H₂O
m(CO₂)/{4M(CO₂)} = m(C₂H₂)/{2M(C₂H₂)}
m(CO₂)=2M(CO₂)m(C₂H₂)/M(C₂H₂)
m(CO₂)=2*44g/mol*38.9g/26g/mol = 131.7 g
131.7 grams of carbon dioxide would be formed
Answer:
0.104 M
Explanation:
<em>A saline solution contains 0.770 g of NaCl (molar mass = 58.55 g/mol) in 133 mL.</em>
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The molar mass of the solute (NaCl) is 58.55 g/mol. The moles corresponding to 0.770 g are:
0.770 g × (1 mol/55.85 g) = 0.0138 mol
The volume of solution is 133 mL. In liters,
133 mL × (1 L/1000 mL) = 0.133 L
The molarity of NaCl is:
M = moles of solute / liters of solution
M = 0.0138 mol / 0.133 L
M = 0.104 M
The reaction is:
Cl2 + 2 KBr --> 2 KCl + Br2
Moles of KCl is
n = m /M = 12 /74 = 0.16 mol
As, twice the moles of KCl is producing from 1 mol of chlorine
mole of Cl2 = 0.16 /2 = 0.08 mol
Mass of Cl2
m /70 = 0.08 = 5.6 g
Hence, 5.6 g mol Cl2 consumed to produce KCl
Answer:
The frequencies of the two lines are:
a) 
b)
When we heat rubidium compound we will see red color.
Explanation:
c = speed of light
= wavelength of light
a) Frequency of the light when wavelength is equal to 
This frequency corresponds to red light
b) Frequency of the light when wavelength is equal to 
This frequency corresponds to violet light
When we heat rubidium compound we will see red color.
