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olga2289 [7]
3 years ago
15

The temperature of a 95.4 g piece of Cu increases from 25.0 °C to 48.0 °C when the Cu absorbs 849 J of heat. What is the specifc

heat of Cu​
Chemistry
1 answer:
melisa1 [442]3 years ago
3 0
<h3>Answer:</h3>

0.387 J/g°C

<h3>Explanation:</h3>
  • To calculate the amount of heat absorbed or released by a substance we need to know its mass, change in temperature and its specific heat capacity.
  • Then to get quantity of heat absorbed or lost we multiply mass by specific heat capacity and change in temperature.
  • That is, Q = mcΔT

in our question we are given;

Mass of copper, m as 95.4 g

Initial temperature = 25 °C

Final temperature = 48 °C

Thus, change in temperature, ΔT = 23°C

Quantity of heat absorbed, Q as 849 J

We are required to calculate the specific heat capacity of copper

Rearranging the formula we get

c = Q ÷ mΔT

Therefore,

Specific heat capacity, c = 849 J ÷ (95.4 g × 23°C)

                                        = 0.3869 J/g°C

                                        = 0.387 J/g°C

Therefore, the specific heat capacity of copper is 0.387 J/g°C

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inn [45]

Answer:

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Explanation:

H:1   O:16

2H2+O2 → 2H2O

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Now,

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5 0
3 years ago
typical seawarer contains 2.7g of salt (sodium chloride,Nacl)per 100ml (100*10-3L).what is the molarity of Nacl in the ocean?​
faust18 [17]

Answer:

Molarity = 0.5 M

Explanation:

Given data:

Mass of NaCl = 2.7 g

Volume = 100 mL(100×10⁻³L)

Molarity of solution = ?

Solution:

Formula:

Molarity = number of moles / volume in litter

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Number of moles = mass/ molar mass

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4 0
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Explanation:

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             Rate = k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y[/tex]

Therefore, the reaction equations by putting the given values will be as follows.

       1.8 \times 10^{-5} = k[0.105]x [0.15]y ............. (1)

       7.2 \times 10^{-5} = k [0.105]x [0.30]y ........... (2)

       3.6 \times 10^{-5} = k [0.0525]x [0.30]y ............ (3)

Now, solving equations (1) and (2) we get the value of y = 2. Therefore, by solving equation (2) and (3)  we get the value of x = 1.

Therefore, expression for rate of the reaction is as follows.

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According to equation (1),

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Thus, we can conclude that rate constant for the given reaction is 7.6 \times 10^{-3} M^{-2} min^{-1}.

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