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3 years ago

Find the sum of the two matrices:

Mathematics

2 answers:

romanna [79]3 years ago

7 0

Answer:

[[5,2],[[4,1],

[3,0]]+[6,7]]

[[9,3],

[9,7]]

Step-by-step explanation:

you add 5+4,2+1,6+3,7+0

scoray [572]3 years ago

7 0

Answer:

9 ... 3

9 ... 7

Step-by-step explanation:

Given

Matrices A and B

Let A ,=

5 2

3 0

And B =

4 1

6 7

Two matrices must have an equal number of rows and columns to be added.

As seen above, the two matrices have 2 rows and 2 columns, so they can be added together

To as these two matrices, we add corresponding rows and columns only.

Take for instance, matric A is represented by

a11 .. a12

a21 .. a22

And

Matric B is represented by

b11 .. b12

b21 .. b22

Their sum can be represented as follows

a11 + b11 .. a12 + b12

a21 + b21 .. a22 + b22.

So, the result of the question, using the above illustration is

a = 5+ 4

b = 2 + 1

c = 3 + 6

d = 0 + 7

So, the matrix becomes

9 ... 3

9 ... 7

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Suppose lines EF and GH are reflected over the line Y equals X to form the lines JK and LM which statement would be true about t

katrin [286]

Answer:

A) JK and LM will be parallel to each other.

Step-by-step explanation:

On reflection on $y=x$ line the x co-ordinate changes with y co-ordinate and y co-ordinate changes with x co-ordinate

$(x,y)\rightarrow (y,x)$

Points on line EF

$(0,6) , (-5,-2)$

On reflection of this line on $y=x$ the new points we get for line JK are

$(6,0),(-2,-5)$

Points on line GH

$(-4,9),(-9,1)$

On reflection on y=x line the new points we get for line LM are

$(9,-4),(1,-9)$

Slope of line JK

$m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-5)-0}{(-2)-6} \\m=\frac{-5}{-8}=\frac{5}{8}$

Slope of line LM

$m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-9)-(-4)}{1-9} \\m=\frac{-9+4}{-8}=\frac{-5}{-8}\\m=\frac{5}{8}$

For two line to be parallel, their slopes will be same.

$m_{JK} =\frac{5}{8} , m_{LM}=\frac{5}{8}$

Since slopes of lines JK and LM are same therefore we can say that these are parallel to each other.

5 0

3 years ago

Answer the following

Murljashka [212]

Answer:

Step-by-step explanation:

7 0

3 years ago

A rancher wants to fence in an area of 1500000 square feet in a rectangular field and then divide it in half with a fence down t

VLD [36.1K]

Answer:

6000 ft

Step-by-step explanation:

Let length of rectangular field=x

Breadth of rectangular field=y

Area of rectangular field= $1500000$ square ft

Area of rectangular field= $l\times b$

Area of rectangular field= $x\time y$

$1500000=xy$

$y=\frac{1500000}{x}$

Fencing used ,P(x)= $x+x+y+y+y=2x+3y$

Substitute the value of y

P(x)= $2x+3(\frac{1500000}{x})$

$P(x)=2x+\frac{4500000}{x}$

Differentiate w.r.t x

$P'(x)=2-\frac{4500000}{x^2}$

Using formula: $\frac{dx^n}{dx}=nx^{n-1}$

$P'(x)=0$

$2-\frac{4500000}{x^2}=0$

$\frac{4500000}{x^2}=2$

$x^2=\frac{4500000}{2}=2250000$

$x=\sqrt{2250000}=1500$

It is always positive because length is always positive.

Again differentiate w.r.t x

$P''(x)=\frac{9000000}{x^3}$

Substitute x=1500

$P''(1500)=\frac{9000000}{(1500)^3}>0$

Hence, fencing is minimum at x=1 500

Substitute x=1 500

$y=\frac{1500000}{1500}=1000$

Length of rectangular field=1500 ft

Breadth of rectangular field=1000 ft

Substitute the values

Shortest length of fence used= $2(1500)+3(1000)=6000 ft$

Hence, the shortest length of fence that the rancher can used=6000 ft

3 0

4 years ago

If h (x) = {(-2,3), (0,4), (1,6), (2, 9)}<br><br> then what set of values represent h-1 (x) ?

vfiekz [6]

Answer:

$h^{-1}(x)=\{(3,-2),(4,0),(6,1),(9,2)\}$

Step-by-step explanation:

Given: $h(x)=\{(-2,3),(0,4),(1,6),(2,9)\}$

To find: $h^{-1}(x)$

Solution:

A relation is said to be a function if each and every element of the domain has a unique image in the co-domain.

Inverse of a function exist if it is both one to one and onto.

$h(x)=\{(-2,3),(0,4),(1,6),(2,9)\}$

$h^{-1}(x)=\{(3,-2),(4,0),(6,1),(9,2)\}$

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3 years ago

What is the remainder in the synthetic division problem below?

NNADVOKAT [17]

Answer:

YES ITS C

Step-by-step explanation:

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