This is a perfect example of exponential decay. In this case the growth factor should be represented by a fraction, and it is! This forest, starting out with apparently ( 800? ) pine trees, has a disease spreading, which kills 1 / 4th of each of the pine trees yearly. Therefore, the pine trees remaining should be 3 / 4.
Respectively 3 / 4 should be the growth factor, starting with 800 pine trees - the start value. This can be represented as such,
- where a = start value, b = growth factor, t = time ( <em>variable quantity</em> )
____
Thus, the function 
can model this problem. The forest after t years should have P( t ) number of pine trees remaining.
Ok I will help you. This middle school?
Answer:
with what my g ????
Step-by-step explanation:
<h2>
Explanation:</h2><h2>
</h2>
<h2>
</h2>
- Let's name the mid point of
as 
- Let's name the mid point of
as 
Then:
So the slope of the line that passes through 
is:
And the slope for BC is:
As you can see, both slopes are zero, so these are horizontal lines.
Answer:
A negative 2’s complement number is even precisely when its last digit is 0 as well.
Step-by-step explanation:
Proof part 1: Assume there exists a 2’s complement negative even number which ends with 1. We can, therefore, express this number as
1 ..... 1 = - (2’s complement of 1 ....1)
= - (0 ... 1 )
≠ even
Since we know precisely that a positive binary number is not even when it ends with a 1. This is a conflict with our assumption. Our assumption is, therefore, wrong.
Proof part 2: Assume there exists a 2’s complement negative odd number which ends with 0. We can, therefore, express this number as
1 ..... 0 = - (2’s complement of 1 ....0)
= - (0 ... 0 )
= even
Since we know precisely that a positive binary number is even when it ends with a 0. This is a conflict with our assumption. Our assumption is, therefore, wrong.
