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3 years ago

How do you this problem?

Mathematics

1 answer:

fgiga [73]3 years ago

3 0

f(x) = ax^2 - 4x + b

If x = -2 , 3 are solutions of zeros function f(x) then b = ?

If x = -2 then a(-2)^2 - 4(-2) + b = 0

4a + 8 + b = 0 (1st)

If x = 3. then a(3)^2 - 4(3) + b = 0

9a - 12 + b = 0 (2nd)

Subtract (2nd) and (1st)

4a + 8 + b = 0 (1st)

9a - 12 + b = 0 (2nd)

--------------------------

-5a + 20 = 0

-5a = -20

a = 4

Substitute a = 4 into 4a + 8 + b = 0 (1st)

4(4) + 8 + b = 0

16 + 8 = -b

b = -24

Answer is A) -24

Double check:

a = 4 and b = -24 so

f(x) = 4x^2 - 4x - 24

zero function:

4x^2 - 4x - 24 = 0

4(x^2 - x - 6) = 0

4(x - 3)(x + 2) = 0

x - 3= 0; x = 3

x = -2 = 0; x = -2

x = -2 , 3 are solutions of the function.

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In Springfield, a specific town in the US, 6 women and 25 men earned bachelor degrees in 2000. In 2010, however, 391 women and 4

Vladimir79 [104]

Answer:

See below

Step-by-step explanation:

For women, the initial number is 6, constant rate of change is w, number of years is x.

Find the rate of change and work out the required formula:

10w + 6 = 391 ⇒ 10w = 385 ⇒ w = 38.5

Formula:

W(x) = 38.5x + 6

Similarly for men, we get:

10m + 25 = 410 ⇒ 10m = 385 ⇒ m = 38.5

Formula:

M(x) = 38.5x + 25

7 0

3 years ago

PLEASSSSSE I NEED HELP BAD HELP PLEASE

charle [14.2K]

Answer:

See explanation

Step-by-step explanation:

Given the equation $3x-4y=12$

A. Create the table of values for at least 4 points.

When $x=0,$

$3\cdot 0-4y=12\\ \\-4y=12\\ \\y=-3$

When $x=2,$

$3\cdot 2-4y=12\\ \\-4y=12-6\\ \\-4y=6\\ \\y=-1.5$

When $x=4,$

$3\cdot 4-4y=12\\ \\-4y=12-12\\ \\-4y=0\\ \\y=0$

When $x=6,$

$3\cdot 6-4y=12\\ \\-4y=12-18\\ \\-4y=-6\\ \\y=1.5$

When $x=8,$

$3\cdot 8-4y=12\\ \\-4y=12-24\\ \\-4y=-12\\ \\y=3$

Thus, the table is

$\begin{array}{cc}x&y\\0&-3\\2&-1.5\\4&0\\6&1.5\\8&3\end{array}$

B. Use the table of values to graph the line on the coordinate plane. Plot given points and connect them with the straight line (see attached diagram).

7 0

3 years ago

Can someone please help me factor 6x^2 - 9x+42

frutty [35]

Answer:

3(2x^2-3x+14)

Step-by-step explanation:

6x^2-9x+42

All three terms have a common factor of 3

3(2x^2-3x+14)

Now let's focus on 2x^2-3x+14 and bring down the factor 3 later

so a=2

b=-3

c=14

Let's try to find two factors for ac that multiply to be a*c and add up to be b.

ac=28

b=-3

-----

ac=7(4)=14(2)=8(2)

Even if I made these pairs with both negatives nothing would give me -3

So you can only go as far as 3(2x^2-3x+14)

Here is another thing to help you if you have ax^2+bx+c and b^2-4ac<0 then it can't be factored (over reals)

6 0

3 years ago

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What number is it if you subtract 2 from a number and the new number and its absolute value are not equal?

ZanzabumX [31]

A negative number probs

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3 years ago

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VikaD [51]

They ate 2/3 together. And, they have 1/3 left!

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3 years ago