Answer:
Thank you ma'am. I have one
Step-by-step explanation:
I need to see the lines to answer your question, please
Answer:
Step-by-step explanation:
For each component, there are only two possible outcomes. Either it fails, or it does not. The components are independent. We want to know how many outcomes until r failures. The expected value is given by

In which r is the number of failures we want and p is the probability of a failure.
In this problem, we have that:
r = 1 because we want the first failed unit.
![p = 0.4[\tex]So[tex]E = \frac{r}{p} = \frac{1}{0.4} = 2.5](https://tex.z-dn.net/?f=p%20%3D%200.4%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3ESo%3C%2Fp%3E%3Cp%3E%5Btex%5DE%20%3D%20%5Cfrac%7Br%7D%7Bp%7D%20%3D%20%5Cfrac%7B1%7D%7B0.4%7D%20%3D%202.5)
The expected number of systems inspected until the first failed unit is 2.5
Answer:
the answer would be 2/5
Step-by-step explanation:
you add up all of the boys to get 8
there are, in total 20 students that can be chosen, so there is an 8/20 chance that it would be a boy, simplified that is 2/5
Answer:
log8 (2.718) = 0.48
Step-by-step explanation:
In 2.718 ÷ In 8 = 0.999896 ÷ 2.07944
= 0.4808