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3 years ago

What is the solution set for 2+6−16=0

Mathematics

1 answer:

Dovator [93]3 years ago

7 0

2+6−16=0

Do the addition first because of using PEMDAS

P= parenthesis

E= exponents

M= multiplication

D= division

A= addition

S= subtraction

8-16= 0

-8= 0

Answer: -8= 0 , does not equal to each other.

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A coffee Merchant combines coffee costing $6 per pound with coffee costing $3.50 per pound how many pounds of each should be use

levacccp [35]

$\bf \begin{array}{lccclll}
&\stackrel{lb}{amount}&\stackrel{lb}{price}&\stackrel{total}{price}\\
&------&------&------\\
\textit{6 per lb coffee}&x&6&6x\\
\textit{3.5 per lb coffee}&y&3.5&3.5y\\
-------&------&------&------\\
mixture&25&5.25&131.25
\end{array}$

same as before, we add the 1st and 3rd columns, since the mixture is just the sum of the elements above it.

$\bf \begin{cases}
x+y=25\implies \boxed{y}=25-x\\
6x+3.5y=131.25\\
----------\\
6x+3.5\left( \boxed{25-x} \right)=131.25
\end{cases}
\\\\\\
6x+87.5-3.5x=131.25\implies 2.5x=131.25-87.5
\\\\\\
2.5x=43.75\implies x=\cfrac{43.75}{2.5}\implies x=17.5$

how many lbs will it be of the 3.50 per lb coffee? well, y = 25 -x.

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3 years ago

If triangle abc ~ triangle def and the scale factor from triangle abc to triangle def 1/5 what are the lengths

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Answer:

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3 years ago

The table shows the number of books donated to a library each month. Suppose the growth continues exponentially.

telo118 [61]

$\bf \begin{array}{ccll}
\stackrel{t}{months}&\stackrel{A}{books}\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
0&80\\
1&100\\
2&125
\end{array}$ , we know that on Month 0, the Books were 80

$\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &80\\
I=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\to &0\\
\end{cases}
\\\\\\
80=I(1+r)^0\implies 80=I\qquad therefore\qquad \boxed{A=80(1+r)^t}$

we also know that on the first month there were 100 books,

$\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &100\\
I=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\to &1\\
\end{cases}
\\\\\\
100=80(1+r)^1\implies \cfrac{100}{80}=1+r\implies \cfrac{5}{4}=1+r
\implies 
\cfrac{5}{4}-1=r
\\\\\\
 \cfrac{1}{4}=r\implies 0.25=r\qquad therefore\qquad \boxed{A=80(1+0.25)^t}$

now, how many books when t = 8? A=80(1+0.25)⁸, or A=80(1.25)⁸.

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3 years ago

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Rob wants to draw a sector with half the arc length of the sector shown. Which method will work?

Fantom [35]

Answer: Multiply the radius,r, by 2. Divide the angle measure, x, by 4.

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3 years ago

If 43 of the 148 reams of paper purchased by a department are used, what is the percentage that remains?

Wewaii [24]

100%/x%=148/43
(100/x)*x=(148/43)*x - we multiply both sides of the equation by x
100=3.44186046512*x - we divide both sides of the equation by (3.44186046512) to get x
100/3.44186046512=x 
29.0540540541=x 
x=29.0540540541

now we have:
43 is 29.0540540541% of 148

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3 years ago

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