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liberstina [14]
3 years ago
7

Simplify: x(x-2)-3x(2x-1)

Mathematics
2 answers:
n200080 [17]3 years ago
6 0

Answer:

x^2-2x-6x^2+3x

x^2+x-6x^2

<em>-5x^2+x</em>

julsineya [31]3 years ago
4 0

Answer:

-5x^2 +x

Step-by-step explanation:

x(x-2)-3x(2x-1)

Distribute

x^2 -2x -6x^2 +3x

Combine like terms

-5x^2 +x

You might be interested in
If f(x) = 3x - 1 and g(x) = x + 2, find (f + g)(x).
Alexxx [7]

Answer:

4x + 1

Step-by-step explanation:

Multiply f + g by x because f + g is in parenthesis:

f(x) + g(x)

Then implement equation #1 for f(x) into our equation:

3x - 1 + g(x)

Then implement the other equation for g(x) into our equation:

3x - 1 + x + 2

Then switch the positions of -1 and +x:

3x + x - 1 + 2

Simmplify:

4x + 1

Pls consider giving my answer the Brainliest! Because it would help and mean a lot! ; )

4 0
4 years ago
Charlie is trying to cover the shape shown with paper. He will NOT be covering the top and the bottom. How much paper will he ne
DENIUS [597]

You need to determine how much paper you need to cover the lateral side of the cylinder shown in the picture. For this, you have to calculate the surface area of the cylinder, which you can do using the following formula:

A=2\pi rh

Where

A is the area

π is the number pi, for the calculations we usually use up to the first two decimal values of this number, 3.14

r is the radius

h is the height of the cylinder

The given cylinder has a height of h=15m and a diameter of d=6m

To calculate the lateral area you need to use the radius. The diameter is twice the radius, so to determine the radius of the cylinder you have to divide the diameter by 2

\begin{gathered} r=\frac{d}{2} \\ r=\frac{6}{2} \\ r=3 \end{gathered}

Now you can calculate the lateral area as follows:

\begin{gathered} A=2\pi rh \\ A=2\cdot3.14\cdot3\cdot15 \\ A=282.6m^2 \end{gathered}

Charlie will need 282.6 m² to cover the lateral side of the cylinder.

6 0
1 year ago
Figure ABCD is transformed to obtain figure A′B′C′D′:
Kisachek [45]

Step-by-step explanation:

part A:

ABCD is transformed to obtain figure A′B′C′D′:

1) by reflection over x-axis, obtain the image :

A(-4,-4) B(-2,-2) C(-2, 1) D(-4, -1)

2) by translation T (7 0), obtain the image :

A'(3,-4) B'(5,-2) C'(5, 1) D'(3, -1)

part B:

the two figures are congruent.

the figures that transformed by reflection either or translation will obtain the images with the same shape and size (congruent)

6 0
3 years ago
Polygon MNOPQ is dilated by a scale factor of 0.8 with the origin as the center of dilation, resulting in the image M’N’O’P’Q’.
N76 [4]
Answer:
slope of M'N' = 1

Explanation:
First, we will need to get the coordinates of points M' and N':
We are given that the dilation factor (k) is 0.8
Therefore:
For point M':
x coordinate of M' = k * x coordinate of M 
x coordinate of M' = 0.8 * 2 = 1.6
y coordinate of M' = k * y coordinate of M
y coordinate of M' = 0.8 * 4 = 3.2
Therefore, coordinates of M' are (1.6 , 3.2)

For point N':
x coordinate of N' = k * x coordinate of N 
x coordinate of N' = 0.8 * 3 = 2.4
y coordinate of N' = k * y coordinate of N
y coordinate of N' = 0.8 * 5 = 4
Therefore, coordinates of M' are (2.4 , 4)

Then, we can get the slope of M'N':
slope = (y2-y1) / (x2-x1)
For M'N':
slope = (3.2-4) / (1.6-2.4)
slope = 1

Hope this helps :)
8 0
4 years ago
Show work and solve for √ ( 5 x − 9 ) − 1 = x.
Mandarinka [93]

sqrt (5x - 9) - 1 = x

sqrt(5x - 9) = x + 1

Square both sides:_

5x - 9 = x^2 + 2x + 1

x^2 - 3x + 10 = 0

(x - 5)(x + 2) = 0

x = 5 or -2.

Lets look for for any extraneous solutions:-

x = 5 ;  sqrt (5*5-9) - 1 = sqrt16 - 1 =  3  and  x = 3  (right hand side of equation)

so x = 5 is a solution

x = -2:  sqrt(5*-2 - 9) - 1 =  sqrt (-19) - 1  and x = -2  so this is extraneous

Answer:- One solution x = 5

4 0
4 years ago
Read 2 more answers
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