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3 years ago

14

BRAINLIESTTT ASAP!!! PLEASE HELP ME :) Explain your answer please and show your steps/work.

1 answer:

algol [13]3 years ago

4 0

Answer:

√x

Step-by-step explanation:

First, simplify -3⁄6 to -½. Next, according to the Negative Exponential Rule, move the denominator to the numerator to get x¹\²:

bⁿ = 1\b⁻ⁿ

Then, according to the Definition of Rational Exponents [part I], rewrite this as a radical, which in this case would be √x. This is when your numerator is 1:

ⁿ√aᵐ = aᵐ\ⁿ

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my You-Tube channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

**I have a video that explains all six exponential rules. It is titled "Six Exponential Procedures". I encourage you to watch the video and gain alot more knowledge from it, so you can better understand the concept.

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Step-by-step explanation:

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3 years ago

In remodeling a house an architect finds that by adding the same amount to each dimension of a 15ft by 19ft rectangular room, th

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Answer:

Step-by-step explanation:

new length=15+x

width=19+x

then area=(15+x)×(19+x)=285+15x+19x+x²=x²+34x+285 ft²

original area=15×19=285 ft²

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At your gym, the bar you lift weighs 45 pounds. You add weights to the bar that are 10 pounds each. If you add 8 weights to the

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Consider the following information related to a set of quantitative sample data:

svlad2 [7]

Answer:

(a) There are outliers

(b) $x$ and $x >62$

Step-by-step explanation:

Given

$\sigma = 14.92$

$\bar x = 22.0$

$q_0 = -24$

$q_1 = 14.5$

$q_2 = 24.5$

$q_3 = 33.5$

$q_4 = 64$

Solving (a): Check for outliers

This is calculated using:

$Lower = Q_1 - (1.5 * IQR)$ --- lower bound of outlier

$Upper = Q_3 +(1.5 * IQR)$ --- upper bound of outlier

Where

$IQR = Q_3 - Q_1$

So, we have:

$IQR = 33.5 - 14.5$

$IQR = 19$

The lower bound of outlier becomes

$Lower = Q_1 - (1.5 * IQR)$

$Lower = 14.5 - (1.5 * 19)$

$Lower = 14.5 - 28.5$

$Lower = -14$

The upper bound of outlier becomes

$Upper = Q_3 +(1.5 * IQR)$

$Upper = 33.5 + 1.5 * 19$

$Upper = 33.5 + 28.5$

$Upper = 62$

So, we have:

$-14 \le x \le 62$ --- the range without outlier

Given that:

$q_0 = -24$ --- This represents the lowest data

$q_4 = 64$ --- This represents the highest data

-24 and 64 are out of range of $-14 \le x \le 62$ .

Hence, there are outliers

Solving (b): The outliers

The outliers are data less than the lower bound (i.e. less than -14) or greater than the upper bound (i.e. 62)

So, the outliers are:

$x$ and $x >62$

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