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Nataliya [291]
3 years ago
12

A car is stopped at a red light. When the light turns green, the car accelerates until it reaches a final velocity of 45 m/s. It

takes the car 12 s to reach this speed. How far does the car travel during this time.
Physics
1 answer:
tigry1 [53]3 years ago
8 0

Answer:

270 m

Explanation:

We can find the distance travelled by the car by using the following suvat equation:

s=(\frac{u+v}{2})t

where

s is the distance travelled

u is the initial velocity

v is the final velocity

t is the time

For the car in this problem,

u = 0

v = 45 m/s

t = 12 s

Substituting into the equation, we find:

s=(\frac{0+45}{2})(12)=270 m

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Answer:

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Using formula of rest,

E=\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{f}^2}{c^2}}}-\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{i}^2}{c^2}}}

E=\dfrac{0.511}{\sqrt{1-\dfrac{(0.900c)^2}{c^2}}}-\dfrac{0.511}{\sqrt{1-\dfrac{(0.500c)^2}{c^2}}}

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E=\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{f}^2}{c^2}}}-\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{i}^2}{c^2}}}

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E=0.350\ Mev

Hence, The energy required to accelerate an electron is 0.582 Mev and 0.350 Mev.

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