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1 year ago

Electrostatics is described as the study of electric charges that can be collected and held in place. Is this true or false?

Physics

1 answer:

Rasek [7]1 year ago

7 0

Electrostatics is described as the study of electric charges that can be collected and held in place.

The above given statement is a true st

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A vertical spring stretches 3.8 cm when a 13-g object is hung from it. The object is replaced with a block of mass 20 g that osc

Alex777 [14]

Answer:

The period of motion is 0.5 second.

Explanation:

Given;

extension of the spring, x = 3.8 cm = 0.038 m

mass of the object, m = 13 g = 0.013 kg

Determine the force constant of the spring, k;

F = kx

k = F / x

k = mg / x

k = (0.013 x 9.8) / 0.038

k = 3.353 N/m

When the object is replaced with a block of mass 20 g, the period of motion is calculated as;

$T = 2\pi\sqrt{\frac{m}{k} } \\\\T = 2\pi\sqrt{\frac{0.02}{3.353} } \\\\T = 0.5 \ second$

Therefore, the period of motion is 0.5 second.

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3 years ago

A watermelon is blown into three pieces by a large firecracker. Two pieces of equal mass m fly away perpendicular to one another

laiz [17]

Answer

given,

watermelon blown into three pieces

two pieces of mass m

both pieces speed = v = 31 m/s

mass of third piece = 3 m

using conservation of mass

$0 = m V \hat{i} + m V \hat{j} + (3\ m)V_3$

$V_3 = \dfrac{V}{3}(-\hat{i}-\hat{j})$

$V_3 = \dfrac{V}{3}\sqrt{1^2+1^2}$

$V_3 = \dfrac{V}{3}\sqrt{2}$

velocity of third component

$V_3 = \dfrac{31}{3}\sqrt{2}$

$V_3 = 14.61\ m/s$

angle

$\theta = tan^{-1}(\dfrac{-1}{-1})$

$\theta = tan^{-1}(1)$

$\theta = 45^0$

5 0

4 years ago

What will the weather be like in your area and your friend’s area over the next 24 hours?

stealth61 [152]

Answer:

hot I checked already in my phone

6 0

3 years ago

29) A load is placed on a 1.5-kg cart. A force of

Goryan [66]

Answer: 0.5 kg
Check photo for work

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3 years ago

The gravitational force law, deduced by Newton in the 1660's, is remarkably similar to Coulomb's law. Recall that the universal

viktelen [127]

Answer:

a. $F=7.83\times 10^{-51} N$

b.Attractive

Explanation:

We are given that

$F=\frac{GM_1M_2}{R^2}$

$G=6.67\times 10^{-11} Nm^2/kg^2$

Mass of an electron, $M_1=9.11\times 10^{-31} kg$

Mass of proton, $M_2=1836\times 9.11\times 10^{-31} kg$

Distance between electron and proton,R= $3.602nm=3.602\times 10^{-9} m$

$1nm=10^{-9} m$

a.Substitute the values then we get

$F=\frac{6.67\times 10^{-11}\times 9.11\times 10^{-31}\times 1836\times 9.11\times 10^{-31}}{(3.602\times 10^{-9})^2}$

$F=7.83\times 10^{-51} N$

b.We know that like charges repel to each other and unlike charges attract to each other.

Proton and electron are unlike charges therefore, the force between proton and electron is attractive.

4 0

3 years ago