Answer:
5.25 times
Step-by-step explanation:
Beverage A and Beverage B are sold in identical cans.
From the above question
Beverage A is 4% sugar.
The portion of Beverage B that is sugar is 0.21.
Converting Portion of sugar in Beverage B to percentage we have :
0.21 × 100
= 21%
How many times more sugar is in Beverage B than Beverage A?
This is calculated as:
% Beverage B/% Beverage A
= 21%/4%
= 5.25
Hence Beverage B has 5.25 times more sugar than Beverage A.
Answer:
Given that events A and B are independent with P(A) = 0.46and; P(B|A)=0.85 determine the value of P(B) , rounding to the nearest thousandth , if necessary .
Step-by-step explanation:
Answer:
x={-3/2,-13/2}
Step-by-step explanation:
3-2|x+4|+3=1
-2|x+4|+6=1
-2|x+4|=-5
|x+4|=5/2
x+4=5/2
x+4=-5/2
x=5/2-4
x=-3/2
x=-5/2-4
x=-13/2
You convert the fractions into 6ths. So 1/3. You would multiply both parts by 2 (top and bottom denominators) and that would be 2/6. 1/2 of 6 is 3/6. So the answer would be 1/6
Answer:
4
Step-by-step explanation:
