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Simora [160]
1 year ago
7

What does the constant 0.9955 reveal about the rate of change of the quantity?

Mathematics
1 answer:
cricket20 [7]1 year ago
7 0

The model given is:

f(t)=290(0.9955)^{60t}

The term in the parentheses represents the change of rate of the model. If the number is the parentheses is less than 1, we call it <em>exponential decay</em>.

If the number in parentheses is bigger than 1, we call it exponential growth.

In this case, the correct option is "decaying"

The number in parentheses let's call it R, is:

R=1-r

Where r is the rate of change. To find it:

\begin{gathered} 0.9955=1-r \\ . \\ r=1-0.9955=0.0045 \end{gathered}

To convert to percentage, we convert by multiplying by 100::

0.0045\cdot100=0.45\%

The second answer is 0.45%

And since t is the time passed in hours, and has a "60" multiplying it, the last answer is: Every 60 hours

<em>The final answer is:</em>

The function is exponentially decaying at a rate of 0.45% evary 60 hours.

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Given in the question,

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t = ln(1/2) / -0.137

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