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3 years ago

Answer:

Mathematics

2 answers:

DaniilM [7]3 years ago

4 0

C it’s c definition of parolleogram I’m just gonna start saying random words

valentinak56 [21]3 years ago

4 0

Answer:

A) Diagonals of a parallelogram bisect each other

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PLEASE ANSWER WILL MARK BRAINLIEST!!!

seropon [69]

Answer:

0.987750947 miles

Step-by-step explanation:

first you find how many inches are in a mile and there are 63360 inches in a mile

2nd you minus 63360 - 776.1 = 62583.9 then you get 62583.9 and put it in miles and your answer is 0.987750947 miles

3 0

1 year ago

each day last week, Ms. wilson walked3/4 mile. what is the total distance, in miles, that Ms. Wilson walked in 4 days?

zloy xaker [14]

Hey there! :D

Since she walks 3/4 a mile a day, we can multiply that by 4.

3/4= .75

4*.75= 3

She walked 3 miles in 4 days.

I hope this helps!
~kaikers

6 0

3 years ago

Read 2 more answers

Given: A(12,9), B(-2,-5) Find: M

VARVARA [1.3K]

Answer:

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

$M = ( \frac{x1 + x2}{2} , \: \frac{y1 + y2}{2} )$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

A(12,9), B(-2,-5)

The midpoint M is

$M = (\frac{12 - 2}{2} , \: \frac{9 - 5}{2} ) \\ = ( \frac{10}{2} , \: \frac{4}{2} )$

We have the final answer as

Hope this helps you

4 0

2 years ago

Read 2 more answers

Which set of side lengths form a right triangle?

vova2212 [387]

Answer:

Answer is 7cm,8cm,10cm

Step-by-step explanation:

A^2+B^2=C^2

6 0

3 years ago

Read 2 more answers

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

$n= 955$ represent the sampel size slected

$x = 812$ number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

The confidence interval for the proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the significance is $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution and we got.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

8 0

3 years ago