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LiRa [457]
3 years ago
5

WILL GIVE BRAINLIEST IF CORRECT!!!

Mathematics
1 answer:
babunello [35]3 years ago
3 0

Answer:

16 total meets

Step-by-step explanation:

it would break even at 8 wins and 8 loss so add them together and get 16 total meets.

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How would u write this equation?
Romashka [77]

Answer:

Step-by-step explanation:

y=a*b^x

pass thro' (1, 7.5) n (3, 16.875)

at x=1, y=a*b=7.5

at x=3, y=a^b^3=16.875

dividing, a*b^3/a*b=16.875/7.5

b^2=2.25

b=+1.5 or -1.5

a=7.5/b

a=5 or -5

y=5*(1.5)^x

or

y=(-5)*(-1.5)^x

6 0
3 years ago
Read 2 more answers
PLEASE HELP!! Find the missing side and round answer to the nearest tenth.
irinina [24]

Answer:

Step-by-step explanation:

opp=x,hyp=16

sin 51°=\frac{x}{16}

cross multiply

sin 51° x 16 =x

0.7771 x 16=x

12.4=x

4 0
3 years ago
1) Find the mean.<br> 14, 2, 12, 11,2, 14, 3, 2, 12<br><br> A) 2<br> B) 8<br> C) 11<br> D)
artcher [175]

Answer:

8

Step-by-step explanation:

Add all the numbers and then divide them by how many numbers there are.

(14 + 2 + 12 + 11 + 2 + 14 + 3 + 2 + 12) = 72

72/9 = 8

6 0
3 years ago
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[-8,6]. B=[
just olya [345]

Answer:

49°

Step-by-step explanation:

Given vectors:

a = [-8, 6]

B = [√7, 3]

θ = ?

To find the angle between the two vectors, we will be using the formula,

                                   a.B = |a||B|cosθ

For simplicity, it is good to first calculate the dot product, and the magnitudes. Then we will substitute the values of the dot product, and the magnitudes of the vectors to solve for the angle.

Calculating the dot product

         a.B = (-8, 6) . (√7, 3)

               = (-8 × √7) + (6 × 3)

               = -8√7 + 18

               = 18 - 8√7

               = 10√7

Calculating the magnitude the vectors

1. The magnitude of vector (-8, 6)    

                |a| = \sqrt{(-8)^{2} + 6^{2}}

                |a| = \sqrt{64 + 36}

                |a| = \sqrt{100}

                |a| = 10

2. The magnitude of vector (√7, 3)

                |B| = \sqrt{(\sqrt{7})^{2} + 3^{2}}

                |B| = \sqrt{7 + 9}

                |B| = \sqrt{16}

                |B| = 4

Calculating the angle between the vectors,

                cosθ = \frac{a.B}{|a||B|}

                cosθ = \frac{10\sqrt{7}}{10 * 4}

                cosθ = 0.6614

                θ = cos⁻¹0.6614

                θ = 48.59°

                θ = 49°

5 0
4 years ago
PLSS HELP MEE!!! 25 POINTS!!!!!
slavikrds [6]

Answer:

what isthe question

Step-by-step explanation:

8 0
3 years ago
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