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attashe74 [19]
4 years ago
9

Help me pls , find the measure of vx that's all I need

Mathematics
1 answer:
Alexxandr [17]4 years ago
4 0

Answer:

VX=26

Step-by-step explanation:

Since YZ is a midpoint of both VW and XW you know that YZ equals 1/2 VX or 2 YZ= VX

2(25-6x) = 9x+8              Simplify the times 2

50-12x = 9x+8                 Subtract 8 from both sides

42-12x = 9x                     Add 12x to both sides

42 = 21x                          Divide by 21

2 = x

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Four circles of unit radius are drawn with centers $(1,0)$, $(-1,0)$, $(0,1)$, and $(0,-1)$. a circle with radius 2 is drawn wit
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Check the picture 1.

The regions contained in an odd number of these 5 circles are

the pink colored region, contained only in the circle with radius 2, 

and the yellow regions, each contained in the intersection of 2 small circles and the third large circle.

So what we need to determine is the "area pink + area yellow".


Consider the second picture.

Let A2 be the area of the right isosceles triangle, and A1 be half of the yellow region.

the region A2 + A1 is called a sector, and it is 1/4 of the area of a unit circle.

A1=A_{sector}-A2= \frac{1}{4} \pi r^2- \frac{1}{2}.1.1= \frac{1}{4} \pi 1^2- \frac{1}{2}=  \frac{1}{4}\pi- \frac{1}{2}


Thus, the overall yellow region is 8A1=8(\frac{1}{4}\pi- \frac{1}{2})=2\pi-4


The purple area is:
 
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(because subtracting all 4 small circles means that each of the 4 separate yellow regions have been subtracted twice)

A_{purple}=\pi.2^2-4(\pi.1^2)+2\pi-4=4\pi-4\pi+2\pi-4=2\pi-4


Finally, the total area is : 2\pi-4+2\pi-4=4\pi-8 (units squared) 



Answer:   6\pi-8    square units

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stuff that WILL HELP YOU STUDYING AND CHECKING YOUR WORK (I PROMISE)

I used these to find your answer quickly^^^

Be sure to actually know the material because I promis you, you WILL see these again on countless amounts of tests

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