Answer:
(a) 185/703
(b) 518/703
(c) 45/703
(d) 140/703
(e) 140/703
(f) 378/703
(g) 185/703
Step-by-step explanation:
Let the event of pledge member be P and event of full member be F
(a)If the first is a pledge, then the second is either a pledge or a member.
required Probabability = [P n (PUF)]
= Pr(PnP) U Pr (PnF)
= 10/38 × 9/37 + 10/38 × 28/38
= 90/1406 + 289/1406 = 370/1406
= 185/703
(b) if the person selected is not a pledge then the person is a full member and the second is either a full member or pledge
The required probability = Fn(FUP) =Pr (FnP) U Pr(FnF)
= 28/38 × 10/37 + 28/38 × 27/37
= 280/1406 + 756/140 = 1036/1406
= 518/703
(c) probability required= Pr(P/P) = Pr(PnP) = 10/38 × 9/37
= 90/1406
= 45/703
(d) Probability required = Pr(F/P)
= Pr(P) nPr(F) = 10/38 × 28/37
= 280/1406
= 140/703
(e) Probability required = Pr(P/F)
= Pr(F) n Pr(P)
= 28/38 × 10/37 =280/1406
=140/704
(f) Probability required = Pr (FnF)
= Pr(F) n Pr(F)
= 28/38 × 27/37= 756/1406
= 378/703
(g) it is the either the first person is a pledge member or a full member
Probability required = Pr[(PnP) U (FnP)]
= Pr(PnP) + Pr(FnP)
= 10/38 × 9/37 + 28/38 × 10/37
= 90/1406 + 280/1406
= 370/1406
= 185/703
(h) see attachment.
The numerical value of this algebraic expression is 123
To solve this algebraic expression, we're going to subtract the numbers indicated in parentheses, and finally, we're going to multiply and <em>add </em>the numbers.
Therefore, we can conclude that the numeric value of this expression will be 123
