1. In snapdragons, the color of the flower is controlled by incomplete dominance. The two alleles are red (R) and white (r). What is genotype of a pink snapdragon? Answer Choice Feedback A. or Incorrect. This snapdragon would be white. B. RR Incorrect. This snapdragon’s phenotype would be red. C. Rr Correct! Since the snapdragon is controlled by incomplete dominance, one allele for red (R), and one for white (W) would result in a pink flower. D. Rw Incorrect. This is not written correctly 2. If a pink-flowered plant is crossed with a white-flowered plant what is the probability of producing a pink-flowered plant? (Hint: Draw a Punnett square to help you answer the question) Answer Choice Feedback A. 25% Incorrect. The genotype for the pink flower is Rr and the genotype for the white flower is or. This would lead to a 50% chance of the offspring having a phenotype of pink. B. 50% Correct! The genotype for the pink flower is Rr and the genotype for the white flower is rr. This would lead to a 50% chance of the offspring having a phenotype of pink. C. 75% Incorrect. The genotype for the pink flower is Rr and the genotype for the white flower is or. This would lead to a 50% chance of the offspring having a phenotype of pink. D. 0% Incorrect. The genotype for the pink flower is Rr and the genotype for the white flower is or. This would lead to a 50% chance of the offspring having a phenotype of pink. 3. Bernadette is blood type O. She has two sisters. One sister has blood type A and the other has blood type B. Using this information and your knowledge of how blood type is determined, determine the genotypes of Bernadette’s parents for this trait. Answer Choice Feedback A. I Ani, IB I Correct! The genotype for type O blood (Bernadette’s type) is “ii”, so both parents must have at least on “i”. Since one sister is type B, one parent must have the IB allele. Since the other sister is type A, then one parent must have the IA allele. B. I A I A, IA I An Incorrect. This would result in children with only type A blood. C. I B me B, IB I B Incorrect. This would result in children with only type B blood D. I B I, IB I Incorrect. This would result in offspring with either type O blood or type B.
DNA is going to be the answer
Answer:
<u>B) Polycystic kidney disease</u>
Explanation:
<u>A) Hypospadias</u>
It is a congenital disease characterized by an abnormal urethral opening on the dorsum of penis.
<u>B) Polycystic kidney disease</u>
It is a disease characterized by the multiple cysts in the kidney as implied by the name.
<u>C) Cystitis</u>
It is defined as the infection of urinary bladder.
<u>D) Dysuria</u>
It is defined as painful urination. It can be due to infection or other underlying disease.
<u>E) Epispadias</u>
It is a congenital disease characterized by an abnormal urethral opening on the ventral surface of penis. It is much less common than hypospadias.
<u>CORRECT ANSWER</u>
From the options, the most appropriate answer is <u>B) Polycystic kidney</u> as it is a disease characterized by the formation of cysts in the kidney. These cysts obstruct urinary flow.
The second one because they can indicate infection and sickness
