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gtnhenbr [62]
4 years ago
8

Multiply: (x + 3)(x – 4) What is the middle term in the simplified product?

Mathematics
2 answers:
Amiraneli [1.4K]4 years ago
8 0

Answer:

-x

Step-by-step explanation:

(x+3)(x-4)

x(x) +x(-4) +3(x) +3(-4)

x^2 + -4x +3x -12

x^2 -x-12

Hope fully this is what a middle term means :)

Masteriza [31]4 years ago
4 0

Answer:

-x

Step-by-step explanation:

(x + 3)(x – 4) = x^2 - 4x + 3x - 12 = x^2 - x - 12

The middle term is -x.

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An overseas telephone company charges $4 for the first minute of talking and then $0.25 for each additional minute. If a woman s
Hoochie [10]

Answer:

<h2>39 minutes</h2>

Step-by-step explanation:

In this problem we can see that there is a constant/flat rate charge of $4 on every first minute

we can model the cost for calls as

y= 4+0.25x------1

where x is the number of extra minutes spent

given that y = $13.75

We can simply substitute our given values into the equation 1 above and solve for x

13.75= 4+0.25x\\\\13.75-4= 0.25x\\\\9.75=0.25x

Divide both sides by 0.25 to find x

x= 9.75/0.25\\\\x=39

6 0
3 years ago
How high would a two story building be if each story was 15ft.? What about a 10-story building? What about a 30-story building
Serhud [2]
This is a very simple question, however having all the words are pretty confusing, right? Don't worry I am going to break it down. First thing you want to do is forget about how many stories are how many feet, because you are trying to find that but are probably getting very confused. So write down that the word EACH= 1-story, Then have 1-story= 15ft. so basically you add 15 to every story. 1=15, 2=30, use this to find the answers 15x= ft---> 15(10)=150ft---> do the last one. If you anymore questions I will break it down further, I used to have a hard time with these.
5 0
3 years ago
What is the graph of y = |x - 3] + 1?<br> O A<br> 1
Mkey [24]
The answer is X=2 and hopefully this helps
7 0
3 years ago
Lowest common multiple of 3,4 and 5
inessss [21]
2x2x3x5=60
The LCM is 60
8 0
3 years ago
Read 2 more answers
Let $DEF$ be an equilateral triangle with side length $3.$ At random, a point $G$ is chosen inside the triangle. Compute the pro
umka21 [38]

|\Omega|=(\text{the area of the triangle})=\dfrac{a^2\sqrt3}{4}=\dfrac{3^2\sqrt3}{4}=\dfrac{9\sqrt3}{4}\\|A|=(\text{the area of the sector})=\dfrac{\alpha\pi r^2}{360}=\dfrac{60\pi \cdot 1^2}{360}=\dfrac{\pi}{6}\\\\\\P(A)=\dfrac{\dfrac{\pi}{6}}{\dfrac{9\sqrt3}{4}}\\\\P(A)=\dfrac{\pi}{6}\cdot\dfrac{4}{9\sqrt3}\\\\P(A)=\dfrac{2\pi}{27\sqrt3}\\\\P(A)=\dfrac{2\pi\sqrt3}{27\cdot3}\\\\P(A)=\dfrac{2\pi\sqrt3}{81}\approx13.4\%

8 0
4 years ago
Read 2 more answers
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