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Bond [772]
3 years ago
9

A store brought 9 cases of light bulbs in May and 8 cases in June. There are 48 light bulbs in a case. How many light bulbs did

the store buy in May and June?
Mathematics
2 answers:
Vitek1552 [10]3 years ago
6 0

Answer:

the answer is 816

Step-by-step explanation:

UkoKoshka [18]3 years ago
5 0
So the store bought 9 cases of lightbulbs and in a case, there are 48.
9 * 48 = the number of lightbulbs in the nine cases. 432 is the number of light bulbs in the 9 cases they bought in May. So then let's move on to the cases they bought in June. Do the same thing 8 * 48 is 384. So then add the two amounts together and then you will get 816 which will be your answer. I hope this helps!
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lesya692 [45]

Answer:

Step-by-step explanation:

Slope = m = -1/4

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2 years ago
Determine the equations of the vertical and horizontal asymptotes, if any, for y=x^3/(x-2)^4
djverab [1.8K]

Answer:

Option a)

Step-by-step explanation:

To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty

Then. x = 2 it's a vertical asintota.

To obtain the horizontal asymptote of the function take the following limit:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4}

if \lim_{x \to \infty}\frac{x^3}{(x-2)^4} = b then y = b is horizontal asymptote

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\lim_{x \to \infty}\frac{x^3}{(x-2)^4} \\\\\\lim_{x \to \infty}\frac{1}{(\infty)} = 0

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3 0
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8 0
3 years ago
Help immediately please
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Answer:

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false

4 0
3 years ago
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