Question

What is the absolute value of the complex number Negative 4 minus StartRoot 2 EndRoot i?

Answer 1

Answer:

The answer is B

Step-by-step explanation:

Answer 2

Answer:

$3\sqrt{2}$

Step-by-step explanation:

For the complex number $a+bi,$ the absolute value is $\sqrt{a^2+b^2}$

Given the complex number $-4-\sqrt{2}i.$ For this complex number,

$a=-4\\ \\b=-\sqrt{2},$

then the absolute value is

$\sqrt{(-4)^2+(-\sqrt{2})^2}=\sqrt{16+2}=\sqrt{18}=3\sqrt{2}$