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3 years ago

Bob is angry with his friend for eating his sandwich. Which conflict best describes this situation?

Mathematics

2 answers:

kow [346]3 years ago

5 0

Answer:Hmmm I think angry

Step-by-step explanation:

Shtirlitz [24]3 years ago

3 0

Answer: character vs character

Step-by-step explanation:

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What is initial value for v(t)= 32000(0.90)^t and the value after 13 yrs

marusya05 [52]

He initial value is 32,000 and the value after 13 yrs is 8133.97

5 0

3 years ago

write and solve an equation to show thw average number of calendars her 3rd period class sold peer week during the four week cha

kari74 [83]

If they sold 89 calendars over 4 weeks, the 'equation' would look like (x = average calendars sold over 4 weeks):
$x = \frac{89}{4}$

If you solve it, you get:
$22 \frac{1}{4}$

Which is equal to 22.25. Hope this helps!

5 0

3 years ago

Find the maxmium area of a rectangular plot of land which can be enclosed by rope of length 60 metres

mario62 [17]

Answer:

225 m²

Step-by-step explanation:

If W is the width of the rectangle, and L is the length, then:

60 = 2W + 2L

A = WL

Use the first equation to solve for one of the variables:

30 = W + L

L = 30 − W

Substitute into the second equation:

A = W (30 − W)

A = 30W − W²

This is a parabola, so we can find the vertex using the formula x = -b/(2a).

W = -30 / (2 × -1)

W = 15

Or, we can use calculus:

dA/dW = 30 − 2W

0 = 30 − 2W

W = 15

Solving for L:

L = 30 − W

L = 15

So the maximum area is:

A = WL

A = (15)(15)

A = 225

3 0

3 years ago

Pleasee help me on my bellwork!!!! i will mark you BRAINLIEST!!!

brilliants [131]

17/2, 8 and 1/2 or 8.5 are all the correct answers.

5 0

3 years ago

Intravenous fluid bags are filled by an automated filling machine. Assume that the fill volumes of the bags are independent, nor

kenny6666 [7]

Answer:

a) 0.0167

b) 0

c) 5.948

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.16 ounces

Standard Deviation, σ = 0.08 ounces

We are given that the distribution of fill volumes of bags is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) Standard deviation of 23 bags

$\displaystyle\frac{S.D}{\sqrt{23}} = \frac{0.08}{\sqrt{23}} = 0.0167$

b) P( fill volume of 23 bags is below 5.95 ounces)

P(x < 5.95)

$P( x < 5.96) = P( z < \displaystyle\frac{5.95 - 6.16}{0.0167}) = P(z < -12.57)$

$= 1 - P(z < 12.57)$

Calculation the value from standard normal z table, we have,

$P(x < 5.95) = 1 - 1 = 0$

c) P( fill volume of 23 bags is below 6 ounces) = 0.001

P(x < 6) = 0.001

$P( x < 6) = P( z < \displaystyle\frac{6 - \mu}{0.0167})$

Calculation the value from standard normal z table, we have,

$P( z \leq -3.09) = 0.001$

$\displaystyle\frac{6 - \mu}{0.0167} = -3.09\\\\\mu = 6 + (0.0167\times -3.09) = 5.948$

If the mean will be 5.948 then the probability that the average of 23 bags is below 6.1 ounces is 0.001.

7 0

3 years ago