How to find the lateral area of the right triangular prism

The area of a square slice of cheese is 25 square inches. The perimeter of the slice of cheese is

maxonik [38]

Answer:

As Per Provided Information

Area of given square slice of cheese is 25 square inches .

We have been asked to determine the perimeter of the slice of cheese .

First we will find the side of square slice of cheese .

Let us assume the side of square slice of cheese be s .

Now Let's Solve

$\boxed{\bf \:Area_{(Square)} = {Side}^{2}}$

Substituting the value and we obtain

$\sf \longrightarrow \: 25 = {s}^{2} \\ \\ \\ \sf \longrightarrow \: \sqrt{25} = s \\ \\ \\ \sf \longrightarrow \: s \: = 5 \: inch$

So, the side of square slice cheese is 5 inch

Now let's calculate the Perimeter of cheese

$\boxed{\bf \: Perimeter_{(Square)} = 4 \times side}$

Substituting the value we obtain

$\longrightarrow \sf \: Perimeter_{(Square)} = 4 \times 5 \\ \\ \\ \longrightarrow \sf \: Perimeter_{(Square)} =20 \: inches$

Therefore,

Perimeter of square slice of cheese is 20 inches .

8 0

1 year ago

Which pair of coordinates represents point p in the graph

Andre45 [30]

Answer:

B. (-3,1)

Step-by-step explanation:

From the graph, point P is 3 units to the left of x-axis and 1 unit to the positive side of y-axis

8 0

3 years ago

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Suppose that Y and Z are points on the number line.

gizmo_the_mogwai [7]

Answer:

Z will be at point 21-22

7 0

2 years ago

One factor in flood safety along a levee is the area that will absorb water should the levee break. The coordinates that make up

Anit [1.1K]

Let

$A(0,0)\\ B (2.8, 2.1)\\C(4.3, 4.4)$

using a graph tool

see the attached figure

The figure is a triangle

we know that

The Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.

Hero's Formula is equal to

$Area=\sqrt{p*(p-a)*(p-b)*(p-c)}$

where

p is is half the perimeter of the triangle

a,b,c are the lengths of the sides of a triangle

so

Step $1$

Find the length sides of the triangle

a) Find the distance AB

$d =\sqrt{(y2-y1)^{2} +(x2-x1)^{2}}$

Substitute

$d =\sqrt{(2.1-0)^{2} +(2.8-0)^{2}}$

$d =3.5\ mi}$

b) Find the distance AC

$d =\sqrt{(y2-y1)^{2} +(x2-x1)^{2}}$

Substitute

$d =\sqrt{(4.4-0)^{2} +(4.3-0)^{2}}$

$d =6.15\ mi}$

c) Find the distance BC

$d =\sqrt{(y2-y1)^{2} +(x2-x1)^{2}}$

Substitute

$d =\sqrt{(4.4-2.1)^{2} +(4.3-2.8)^{2}}$

$d =2.75\ mi}$

Step $2$

Find the perimeter of the triangle

$Perimeter= 3.5+6.15+2.75 =12.4\ mi$

Find the half of the perimeter

$p=\frac{12.4}{2} = 6.2\ mi$

Step $3$

Find the area of the triangle

$Area=\sqrt{6.2*(6.2-3.5)*(6.2-6.15)*(6.2-2.75)}$

$Area=\sqrt{6.2*(2.7)*(0.05)*(3.45)}$

$Area= 1.69\ mi^{2}$

therefore

the answer is the option

a) 1.65 mi^2.

4 0

2 years ago

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Rachel has a box in the shape of a prism with a square base. The capacity of the box is 150 cubic inches. The height of the box

hjlf

V = s²h

150 = s²h 
150 = s²(3/2)s 
(2/3)150 = s³ 
100 = s³ 
s = ∛100 (approx 4.642 in)

6 0

3 years ago