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Answer:
There can be 14,040,000 different passwords
Step-by-step explanation:
Number of permutations to order 3 letters and 2 numbers (total 5)
(AAANN, AANNA,AANAN,...)
= 5! / (3! 2!)
= 120 / (6*2)
= 10
For each permutation, the three distinct (English) letters can be arranged in
26!/(26-3)! = 26!/23! = 26*25*24 = 15600 ways
For each permutation, the two distinct digits can be arranged in
10!/(10-2)! = 10!/8! = 10*9 = 90 ways.
So the total number of distinct passwords is the product of all three permutations,
N = 10 * 15600 * 90 = 14,040,000
Answer:
The p -value is less than 0.001.
Step-by-step explanation:
Given information:
Sample size = 25 chips
Sample mean = 985
Sample standard deviation = 10
Let as assume that sample is distributed normally.
The formula for test statistic

where,
is sample mean
μ is population mean.
s is sample standard deviation.
n is sample size.
The value of test statistic is



The p-value is

Therefore the p -value is less than 0.001.
Hi, there
<u>Question:Ms. Lynch has 21 coins in nickels and dimes. Their total value is $1. 65. How many of each coin does she have?</u>
Explanation:
1.65 x 21
Answer 34.65