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Burka [1]
2 years ago
9

A rectangular piece of sheet metal has a length that is 10 10 in. less than twice the width. A square piece 5 5 in. on a side is

cut from each corner. The sides are then turned up to form an uncovered box of volume 1210 1210 in. cubed in.3 Find the length and width of the original piece of metal.
Mathematics
1 answer:
Hatshy [7]2 years ago
4 0

Answer:

  • length: 32 in
  • width: 21 in

Step-by-step explanation:

If the width of the original piece of sheet metal is x, then the length is 2x-10. Subtracting a 5" square from each corner makes the bottom of the box have dimensions (x-10) and (2x-20). The volume of the box is then ...

  5(x -10)(2x -20) = 1210 . . . . . . volume is the product of the dimensions

  10(x -10)² = 1210 = 10(11²) . . . . factor the equation

  (x -10)² = 11² . . . . . . . . divide by 10

  x = 11 + 10 = 21 . . . . . .take the square root, add 10

The length and width of the original piece of sheet metal were 32 inches and 21 inches, respectively.

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The formula for calculating the percent change in a value between two points in time is:
p
=
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⋅
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Where:
p
is the percent change - what we are solving for in this problem.
N
is the New Value - 62 inches in this problem.
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