Answer: The picture contains the answer and the steps
We have that
f(x) = (x – 5)³(x + 2)²
we know that
<span>the roots can touch or cross the x axis
</span>The way you can tell if the graph is going to cross the x-axis or just touch the x-axis is by looking at the power of the factor.
(x - 5)³ has a power of 3 which is an ODD number. An ODD power means that the graph will cross through the x-axis.
(x + 2)² has a power of 2 which is an EVEN number. An EVEN power means that the graph will touch the x-axis.
therefore
the answer is<span>
the graph of f(x) touch the x axis for the root x=-2
</span>
see the attached figure
Answer:
A=-3/2
B=3
c=3/2
a=-2
Step-by-step explanation:
Knowing that for
,
when t<0 and using the definition of charge

The first term corresponds to q(0), the charge accumulated before t=0, in this case it luckily gives zero so we don't have to worry about it.
Let's proceed and integrate
then when t>0
![i(t)=3\int_0^t \left[ \int_0^tdt'-\inte_0^t e^{-2t'}dt' \right]dt'=3\left[ t+\frac{1}{2}\left( e^{-2t}-1 \right) \right]=3t+\frac{3}{2}e^{-2t}-\frac{3}{2}\,\, C](https://tex.z-dn.net/?f=i%28t%29%3D3%5Cint_0%5Et%20%5Cleft%5B%20%5Cint_0%5Etdt%27-%5Cinte_0%5Et%20e%5E%7B-2t%27%7Ddt%27%20%5Cright%5Ddt%27%3D3%5Cleft%5B%20t%2B%5Cfrac%7B1%7D%7B2%7D%5Cleft%28%20e%5E%7B-2t%7D-1%20%5Cright%29%20%5Cright%5D%3D3t%2B%5Cfrac%7B3%7D%7B2%7De%5E%7B-2t%7D-%5Cfrac%7B3%7D%7B2%7D%5C%2C%5C%2C%20C)
It is clear that:
A=-3/2
B=3
c=3/2
a=-2
Step-by-step explanation:
for mean w. you have to add up all the values (cat weights) and divide them by the number of cats
and for median w. you need to compare the values from the smallest to the largest and cross out the numbers from the ends. Since there are 6 cats here (odd number) you will have 2 values left. Add them up and divide them by 2 (since there are 2)
Answer:
x=4
Step-by-step explanation:
(2x+3)^2=121
2x+3=square root of 121
2x+3=11
2x=11-3
2x=8
x=4
(in a square all sides are equal therefore area =length ×width where length and width=2x+3)