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Rashid [163]
3 years ago
5

Find the "a" value so that the equation ax^2-10x + 25 = 0 has two equal, real roots.

Mathematics
1 answer:
alukav5142 [94]3 years ago
3 0

Answer:

Step-by-step explanation:

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X = 9   X/-9 +9=8  9<span>/-9 +9=8 </span>
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The focal points of an ellipse are (12, 0) and (−12, 0), and the point (12, 7) is on the ellipse. Find the points where this cur
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Answer:

x - ( 16 , 0 ) , ( -16 , 0 )

y - ( 0 ,  4√7 ) , ( 0 , -4√7)

Step-by-step explanation:

Solution:

- The sum of the distances from a point on the ellipse to its foci is constant. You have both foci and a point, so you can find the sum of the distances.

-Then you can find the vertices since they are points on the ellipse on the x-axis whose sum of distances to the foci are that value.

- The 7 in y coordinate of (12,7) is the length of semi-latus rectum. Also c is 12:

                                     c^2 = a^2 + b^2

Where, a: x-intercept

            b: y-intercept

- The length of semi-latus rectum is given by:

                                     b^2 = 7*a

- Substitute latus rectum expression in the first one we get:

                                    c^2 = a^2 + 7a

                                    a^2 + 7a - 144 = 0

                                    ( a - 16 ) * ( a - 9 ) = 0

                                    a = +/- ( 16 )

- The y-intercept we will use latus rectum expression again:

                                    b = +/- √(7*16)

                                    b = +/- 4√7

- The intercepts are:

                                    x - ( 16 , 0 ) , ( -16 , 0 )

                                    y - ( 0 ,  4√7 ) , ( 0 , -4√7)  

                                     

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3 years ago
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Answer:

p > 80

Step-by-step explanation:

Given

Points = More than 80

Required [Missing from the question]

Represent as an inequality

Let p represents the number of points.

More than means greater than i.e. >

Hence, more than 80 is represented as;

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