Please help and thank you

Given f (x) = startlayout enlarged left-brace first row 3 startroot 2 x minus 1 endroot, for x less-than-or-equal-to 2 second ro

qwelly [4]

These 2 equations has no solution and the equations are independent of each other.

What is liner equation with two variable?

An equation is said to be linear equation in two variables if it is written in the form of ax + by + c=0, where a, b & c are real numbers and the coefficients of x and y, i.e a and b respectively, are not equal to zero.
For example, 10x+4y = 3 and -x+5y = 2 are linear equations in two variables.

-10x² -10y² = -300 ----a

5x² + 5y² = 150 ---- b

While trying to solve this,

We can multiply the eq. b by 2 so we will get eq. c and then add to eq. a we will get 0 as the solution.

10x² + 10y² = 300 ----c

-10x² -10y² = -300 ---a

Everything cutoff, we will get 0, and there is no solution to these equations.

Learn more about liner equation with two variable brainly.com/question/16933755

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8 0

2 years ago

Y=4x^2-36 solve the following quadratic function by utilizing the square root method x=?

Luda [366]

Answer:

This ans is easily solved by using algebraic identities a²- b² = (a+b) (a-b)

Step-by-step explanation:

1. convert into Identity

2. solve quadratic equation that formed.

7 0

2 years ago

As part of a traffic safety campaign a speed detector was used to record speed in the entrance driveway to the Jefferson High Sc

Firlakuza [10]

1. The highest speed is 39 mph. 2. 50 percent of the students drove between 15 and 28 mph. 3. A box and whisker plot shows the median speed. 4. 20 is the median speed for this data set. 5. A box and whisker plot is helpful in plotting variations in data and making it easy to read. It is also useful when there are multiple sets of data.

5 0

3 years ago

In the past, 35% of the students at ABC University were in the Business College, 35% of the students were in the Liberal Arts Co

sukhopar [10]

Answer:

a. proportions have not changed significantly

Step-by-step explanation:

Given

Business College= 35 %

Arts College= 35 %

Education College = 30%

Calculated

Business College = 90/300= 9/30= 0.3 or 30%

Arts College= 120/300= 12/30= 2/5= 0.4 or 40%

Education College= 90/300= 9/30 = 0.3 or 30%

First we find the mean and variance of the three colleges using the formulas :

Mean = np

Standard Deviation= s= $\sqrt{npq\\}$

Business College

Mean = np =300*0.3= 90

Standard Deviation= s= $\sqrt{npq\\}$ = $\sqrt{0.3*0.7*300}$ = 7.94

Arts College

Mean = np =300*0.4= 120

Standard Deviation= s= $\sqrt{npq\\}$ = $\sqrt{0.4*0.6*300}$ = 8.49

Education College

Mean = np =300*0.3= 90

Standard Deviation= s= $\sqrt{npq\\}$ = $\sqrt{0.3*0.7*300}$ = 7.94

Now calculating the previous means with the same number of students

Business College

Mean = np =300*0.35= 105

Arts College

Mean = np =300*0.35= 105

Education College:

Mean = np =300*0.3= 90

Now formulate the null and alternative hypothesis

Business College

90≤ Mean≥105

Arts College

105 ≤ Mean≥ 120

Education College

U0 : mean= 90 U1: mean ≠ 90

From these we conclude that the proportions have not changed significantly meaning that it falls outside the critical region.

8 0

4 years ago

Need helpppppp thank you!!

lesya692 [45]

Answer:

I would say 50%

Step-by-step explanation:

5 0

3 years ago

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