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4 years ago

Describe a real-world situation where the relationship is linear and nonproportional.

Mathematics

1 answer:

Thepotemich [5.8K]4 years ago

3 0

A 10-inch candle burns at a constant rate of 1 inch per hour.

Rule in words: To determine the height of the candle multiply the number of hours that the candle burns by 1 inch per hour, and subtract the product from the candle’s initial height (10 inches).

Rule in Equation: If y represents the height of the candle after x hours of burning, then the relationship can be expressed as an equation in the form y = mx + b, where m represents the rate at which the candle burns (1 inch per hour) and b represents the initial height of the candle (10 inches).

Height of Candle = Rate at which it Burns • Number of Hours Burned + Initial Height
y = -1 • x + 10, or y = 10 -1x

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Graph the circle (x+6)^2 + (y+5)^2 =9

Andrei [34K]

Answer:

This a circle centered at the point $(-6,-5)$ , and of radius "3" as it is shown in the attached image.

Step-by-step explanation:

Recall that the standard formula for a circle of radius "R", and centered at the point $(x_0,y_0)$ is given by:

$(x-x_0)^2+(y-y_0)^2=R^2$

Therefore, in our case, by looking at the standard equation they give us, we extract the following info:

1) $R^2 = 9\,\,\,then\,\,\,R=3$ since the radius must be a positive number and ( $R=-3$ ) is not a viable answer.

2) $x_0=-6$ for ( $x-x_0$ ) to equal $(x+6)$

3) $y_0=-5$ for ( $y-y_0$ ) to equal $(y+5)$

Therefore, we are in the presence of a circle centered at the point $(-6,-5)$ , and of radius "3". That is what we draw as seen in the attached image.

5 0

3 years ago

A survey of 279 SPC students was taken at registration. Of those surveyed: 51 students had signed up for a Language Arts course

stepladder [879]

Treating the amounts as Venn sets, we have that 161 students signed up for only Math, considering that 40 did not sign for any.

For this problem, we consider the following sets:

Set A: Students that have signed up for Arts.

Set B: Students that have signed up for Humanities.

Set C: Students that have signed up for Math.

4 students had signed up for all three courses students, hence:

(A ∩ B ∩ C) = 4.

8 students had signed up for both a Math and Humanities, hence:

(B ∩ C) + (A ∩ B ∩ C) = 8

(B ∩ C) = 8.

18 students had signed up for both a Math and Language Arts, hence:

(A ∩ C) + (A ∩ B ∩ C) = 18

(A ∩ C) = 14.

9 students had signed up for both a Language Arts and Humanities, hence:

(A ∩ B) + (A ∩ B ∩ C) = 9

(A ∩ B) = 5.

36 students had signed up for a Humanities course, hence:

B + (A ∩ B) + (B ∩ C) + (A ∩ B ∩ C) = 36

B + 5 + 8 + 4 = 36

B = 19.

51 students had signed up for a Language Arts course, hence:

A + (A ∩ B) + (A ∩ C) + (A ∩ B ∩ C) = 36

A + 5 + 14 + 4 = 51

A = 28.

Considering that there are 279 students, and supposing 40 did not sign for any course, we have that:

A + B + C + (A ∩ B) + (B ∩ C) + (A ∩ C) + (A ∩ B ∩ C) + 40 = 279.

28 + 19 + C + 5 + 8 + 14 + 4 + 40 = 279

118 + C = 279

C = 161

161 students signed up for only Math, considering that 40 did not sign for any.

More can be learned about Venn sets at brainly.com/question/24388608

#SPJ1

3 0

2 years ago

Which event has exactly 12 possible outcomes?

s2008m [1.1K]

Answer:

rolling a number cube with sides labeled 1-6 and tossing a coin

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Is quadrilateral JKLM the result of a dilation of quadrilateral ABCD by a scale factor of 2? Why or why not? Yes, because sides

scZoUnD [109]

I'm taking this pre-test right now. I think the answer is "No, because sides JM and KL have different slopes from sides AD and BC."
After looking closely, it looks like JM and KL are slightly steeper lines than AD and BC.

7 0

3 years ago

Read 2 more answers

Is 196, 28, 4, 4/7, a geometric sequence?

Paul [167]

Answer:

Step-by-step explanation:

If there is a common ratio between consecutive terms in the sequence then it is geometric, that is

$\frac{28}{196}$ = $\frac{1}{7}$