5{-3.4k-7} + {3k+21}
1 answer:
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Answer and Explanation:
Given : Five males with an X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the X-linked genetic disorder.
To find :
a. Does the table show a probability distribution?
b. Find the mean and standard deviation of the random variable x.
Solution :
a) To determine that table shows a probability distribution we add up all six probabilities if the sum is 1 then it is a valid distribution.
Yes it is a probability distribution.
b) First we create the table as per requirements,
x P(x) xP(x) x² x²P(x)
0 0.029 0 0 0
1 0.147 0.147 1 0.147
2 0.324 0.648 4 1.296
3 0.324 0.972 9 2.916
4 0.147 0.588 16 2.352
5 0.029 0.145 25 0.725
∑P(x)=1 ∑xP(x)=2.5 ∑x²P(x)=7.436
The mean of the random variable is
The standard deviation of the random sample is
Therefore, The mean is 2.5 and the standard deviation is 1.08.
Answer:
I wasn't sure how you're supposed to answer, so the answers for each scenario are in the explanation!
Step-by-step explanation:
From here, there can be a few different answers:
The exact answer is A=36π inches^2.
If you need to round, round this to wherever you need it: A=113.0973355292326... inches^2
If you're using 3.14 for pi, the answer is A=113.04 inches^2.