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mel-nik [20]
3 years ago
14

For males the expected pulse rate is 70 per second and the standard deviation is 10 per second. For women the expected pulse rat

e is 77 per second and the standard deviation is 12 per second. Let !X ¼ the sample average pulse rate for a random sample of 40 men and let !Y ¼ the sample average pulse rate for a random sample of 36 women.What is the approximate distribution of \overline{X}-\overline{Y} ? Justify your answer.
Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
5 0

Answer:

Normal

Step-by-step explanation:

Given are the pulse rates average and std deviation for men and women.

Men Women Difference

Pulse rate per second 70 77 -7

Std dev per second 10 12  

Variance 100 144 244

n 40 36  

Variance/n 2.5 4 6.5

Std error   2.549509757

The first one represents X that of men and ii one that of women Y.

\bar X -\bar Y is Normal

Mean = difference in means

and Std dev of difference = \sqrt{\frac{\sigma_1^2 }{n_1} +\frac{\sigma_2^2 }{n_2}}

Thus using the above we calculate the distribution of difference of means is Normal with mean = -7 and std error = 2.5495

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Answer:

minimum value = 1.0 , the lower quartile = 2.3, the middle value = 3.5.

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Step-by-step explanation:

Five Number Summary of any data consists basically of 5 data sets.

1) The minimum Value

2)The first (lower) quartile

3) The middle value (Median)

4) The third (upper) quartile

5)The maximum value

Now, the given data is  4.0, 1.0, 1.5, 1.6, 2.0, 2.2, 2.4, 2.7, 3.4, 3.4, 3.5, 3.6, 3.6, 3.7, 3.7, 3.9, 4.1, 5.8, 4.1, 7.3

Arrange it in the ascending order,

1.0, 1.5, 1.6, 2.0, 2.2, 2.4, 2.7, 3.4, 3.4, 3.5, 3.6, 3.6, 3.7, 3.7, 3.9, 4.0, 4.1, 4.1, 5.8, 7.3

Here,

1) The minimum Value  is 1.0

2)The first (lower) quartile  is  2.3.

3) The middle value (Median)  is 3.5.

4) The third (upper) quartile is  3.95.

5)The maximum value  is 7.3.

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The correct answer is D.

Have a good day! :)

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