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kiruha [24]
4 years ago
8

Why is it important to consider multiplicity when determining the roots of a polynomial equation? Write your response, citing ma

thematical reasons and providing examples that you create In order to receive full credit for this prompt, please answer the following questions: What it multiplicity? What does it tell us? Why must we take multiplicity into account when talking about the number of roots a polynomial has? What does multiplicity tell us about how the graph behaves at the roots?

Mathematics
1 answer:
Svetradugi [14.3K]4 years ago
6 0

Answer:

Step-by-step explanation:

The multiplicity of a root of a polynomial equation is the number of times it appears in the solution.

Multiplicity is important because it can tell us two things about the polynomial that we work on and how it is graphed. first: it tells us the number repeating factor a polynomial has to determine the number of the real (positive or negative) roots and complex roots of the polynomial.

About graph behaves at the roots : Behavior of a polynomial function near a multiple root

The root −4 is a 'simple' root (of multiplicity 1), and therefore the graph crosses the x-axis at this root. The root 1 is of even multiplicity and therefore the graph bounces off the x-axis at this root.

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Find the solution of the given initial value problem in explicit form. y′=(1−5x)y2, y(0)=−12 Enclose numerators and denominators
Nata [24]

Answer:

The solution is y=-\frac{12}{12x-30x^2+1}.

Step-by-step explanation:

A first order differential equation y'=f(x,y) is called a separable equation if the function f(x,y) can be factored into the product of two functions of x and y:

f(x,y)=p(x)h(y)

where p(x) and h(y) are continuous functions.

We have the following differential equation

y'=(1-5x)y^2, \quad y(0)=-12

In the given case p(x)=1-5x and h(y)=y^2.

We divide the equation by h(y) and move dx to the right side:

\frac{1}{y^2}dy\:=(1-5x)dx

Next, integrate both sides:

\int \frac{1}{y^2}dy\:=\int(1-5x)dx\\\\-\frac{1}{y}=x-\frac{5x^2}{2}+C

Now, we solve for y

-\frac{1}{y}=x-\frac{5x^2}{2}+C\\-\frac{1}{y}\cdot \:2y=x\cdot \:2y-\frac{5x^2}{2}\cdot \:2y+C\cdot \:2y\\-2=2yx-5yx^2+2Cy\\y\left(2x-5x^2+2C\right)=-2\\\\y=-\frac{2}{2x-5x^2+2C}

We use the initial condition y(0)=-12 to find the value of C.

-12=-\frac{2}{2\left(0\right)-5\left(0\right)^2+2C}\\-12=-\frac{1}{c}\\c=\frac{1}{12}

Therefore,

y=-\frac{2}{2x-5x^2+2(\frac{1}{12})}\\y=-\frac{12}{12x-30x^2+1}

4 0
3 years ago
Use The Scale Factor 1:12 To Find The Missing Dimension
adell [148]

Answer:

The length of the model is 21 inches

Step-by-step explanation:

we have

The scale factor

\frac{1}{12}

That means

1 unit in the model represent 12 units in the actual

1 inch in the model represent 12 inches in the actual

Remember that

1\ ft=12\ in

so

1 inch in the model represent 1 ft in the actual

The scale factor is

\frac{1}{1}\ \frac{in}{ft}

therefore

21 ft in the actual represent 21 inches in the model

6 0
3 years ago
Luke made cookies he used 1/2 of a cup of flour and 2/5 of cup of sugar. How much more flour than sugar did Luke use
VLD [36.1K]

Answer:

1/10

Step-by-step explanation:

2/5 a cup of sugar

1/2 a cup of flour

-Convert to 10ths:

4/10 of sugar, and 5/10 of flour.

Luke used 1/10 more flour than sugar.

8 0
2 years ago
QUESTION 17 The sum of two numbers is 53. The larger number is 1 less than 2 times the smaller. What are the two numbers?
Crazy boy [7]

I only know 17 which it should be D

7 0
3 years ago
A football field is a 64-meter-wide, 100-meter-long rectangle. What is the length of a diagonal ofa football field to the neares
lutik1710 [3]

Answer:

A rectangular football field is 64 meters wide and 100 meters long. A player runs from one corner of the firmed in a diagonal line to the opposite corner. ... How much shorter is it to run across the field than around it ( nearest tenth)? ... Substitute the length of the sides (7 in, 25in n) into the Pythagorean theorem.

Step-by-step explanation:

im srry if it is wrong but i tried

3 0
3 years ago
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